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2 years ago

How many times does the graph of the function below intersect or touch the

Mathematics

1 answer:

Nitella [24]2 years ago

3 0

Answer:

The graph of the function only touches once, so it is B. 1

Step-by-step explanation:

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a candy bar box is in the shape of a triangular prism. The volume of the box is 1200 cubic centimetres. The base is 10 centimetr

Elina [12.6K]

Answer:

Step-by-step explanation:

$V=\frac{HBL}{2}\\ \\ H=\frac{2V}{BL}\\ \\ H=\frac{2(1200)}{10(20)}\\ \\ H=12cm$

7 0

2 years ago

Determine whether a probability distribution is given. If a probability distribution is given, find its mean and standard deviat

drek231 [11]

Answer:

$E(X) = \sum_{i=1}^n X_i P(X_i) = 0*0.031 +1*0.156+ 2*0.313+3*0.313+ 4*0.156+ 5*0.031 = 2.5$

We can find the second moment given by:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 0^2*0.031 +1^2*0.156+ 2^2*0.313+3^2*0.313+ 4^2*0.156+ 5^2*0.031 =7.496$

And we can calculate the variance with this formula:

$Var(X) =E(X^2) -[E(X)]^2 = 7.496 -(2.5)^2 = 1.246$

And the deviation is:

$Sd(X) = \sqrt{1.246}= 1.116$

Step-by-step explanation:

For this case we have the following probability distribution given:

X 0 1 2 3 4 5

P(X) 0.031 0.156 0.313 0.313 0.156 0.031

The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete.

The variance of a random variable X represent the spread of the possible values of the variable. The variance of X is written as Var(X).

We can verify that:

$\sum_{i=1}^n P(X_i) = 1$

And $P(X_i) \geq 0, \forall x_i$

So then we have a probability distribution

We can calculate the expected value with the following formula:

$E(X) = \sum_{i=1}^n X_i P(X_i) = 0*0.031 +1*0.156+ 2*0.313+3*0.313+ 4*0.156+ 5*0.031 = 2.5$

We can find the second moment given by:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 0^2*0.031 +1^2*0.156+ 2^2*0.313+3^2*0.313+ 4^2*0.156+ 5^2*0.031 =7.496$

And we can calculate the variance with this formula:

$Var(X) =E(X^2) -[E(X)]^2 = 7.496 -(2.5)^2 = 1.246$

And the deviation is:

$Sd(X) = \sqrt{1.246}= 1.116$

6 0

3 years ago

PLEASE help me with these 2 questions!!

dimaraw [331]

You do not want the "b" since two of the equations start off at 0 kites.

x=kites purchased

Kities : y=8x

Windy Kites: y=20x

From there, all you need to do is plug in the kite purchased number replacing x.

4 0

3 years ago

amid has gained weight he now weighs 88kg which is 10% higher than his normal weight. what is his normal weight?

dybincka [34]

Answer:

88*0.9= 79.2 (since it's 10% higher, multiply by .9 to find out what 90% of 88 is

you also could've done 88*0.1=8.8 and then subtract 8.8 from 88 and get 79.2

either way his normal weight is 79.2kg

5 0

2 years ago

nina bought a computer mouse for 9.00 and she paid with a $20 bill how much change does she get back?

Alex777 [14]

Answer:

11 bucks

Step-by-step explanation:

8 0

2 years ago