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kifflom [539]
3 years ago
13

4. How many moles of water are produced when 3.25 moles of CO2 are formed?

Chemistry
1 answer:
Tju [1.3M]3 years ago
7 0

Answer:

6.50 mol

Explanation:

The question is incomplete but I looked it up on the web.

<em>How many moles of water are produced when 3.25 moles of CO₂ are formed during the combustion of methyl alcohol (CH₃OH)?</em>

Step 1: Write the balanced equation

2 CH₃OH +  3 O₂ → 2 CO₂ + 4 H₂O

Step 2: Establish the appropriate molar ratio

According to the balanced equation, the molar ratio of CO₂ to H₂O is 2:4.

Step 3: Calculate the moles of water formed with 3.25 moles of carbon dioxide

We will use the established molar ratio.

3.25 mol CO₂ × (4 mol H₂O/ 2 mol CO₂) = 6.50 mol H₂O

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How many grams in 82 moles of CO2
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What is the oxidation number for iodine in Mg(IO3)2 ?
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Nitric acid and nitrogen monoxide react to form nitrogen dioxide and water, like this: At a certain temperature, a chemist finds
poizon [28]

Answer:

K = 3.3

Explanation:

Nitric acid, HNO3, reacts with nitrogen monoxide, NO, to produce nitrogen dioxide, NO2 and water H2O as follows:

2HNO3(g) + NO(g) → 3NO2(g) + H2O(g)

Where equilibrium constant, K, is:

K = [NO2]³[H2O] / [HNO3]²[NO]

<em>[] is the molar concentration of each species at equilibrium.</em>

To solve this question we need to find molarity of each gas and replace these in the equation as follows:

<em>[NO2] -Molar mass NO2-46.0g/mol-</em>

18.6g * (1mol/46.0g) = 0.404mol / 7.7L = 0.0525M

<em>[H2O] -Molar mass:18.01g/mol- </em>

236.7g * (1mol/18.01g) = 13.14 moles / 7.7L = 1.707M

<em>[HNO3] -Molar mass:53.01g/mol-</em>

16.2g * (1mol/53.01g) = 0.3056 moles / 7.7L = 0.0397M

<em>[NO] -Molar mass: 30.0g/mol-</em>

11.0g * (1mol/30.0g) = 0.367 moles / 7.7L = 0.0476M

Replacing:

K = [NO2]³[H2O] / [HNO3]²[NO]

K = [0.0525M]³[1.707M] / [0.0397M]²[0.0476M]

<h3>K = 3.3</h3>

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4 0
3 years ago
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