Plz solve these two problems plz I'll give brainlyest
2 answers:
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When building a Venn Diagram, I always start from the area with the most overlap to the areas of least overlap. Once you have placed the 3 in the middle, you have counted those people, and therefore you must subtract them from the other surveys. Example: since there are 3 people that like all three subjects, now only have 5 students that like just math and English instead of 8.
Therefore:
A) 36 Students were in the survey
*Add all the numbers within the Venn diagram up. Overlapping doesn't matter because no one is double counted.
B) 6 People liked only Math
*Can't touch any other circle but Math
C) 20 Students liked English and math, but not history
*You add 9+5+6, since these bubbles are not overlapping with history.
I Hope this helps and let me know if you have any further questions!
Therefore:
A) 36 Students were in the survey
*Add all the numbers within the Venn diagram up. Overlapping doesn't matter because no one is double counted.
B) 6 People liked only Math
*Can't touch any other circle but Math
C) 20 Students liked English and math, but not history
*You add 9+5+6, since these bubbles are not overlapping with history.
I Hope this helps and let me know if you have any further questions!
Answer:
x = 3 units
SV = 2 units
Step-by-step explanation:
In QR and ST are chords such that:
QR = ST = 4
That is both the chords are equal in measure.
Equal chords are at equal distance from the center of the circle. Therefore,
VZ = UZ
4x - 6 = 6
4x = 6 + 6
4x = 12
x = 12/4
x = 3 units
Since, perpendicular dropped from the center of the circle bisects the chord.