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3 years ago

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A building that is 15 meters tall casts a shadow that is 22meters. At the same time, A tree that is 9 meters tall casts a shadow

. How long is the tree’s shadow?

1 answer:

Arte-miy333 [17]3 years ago

3 0

Answer:

The answer is that the shadow of the tree is 16 meters tall

Step-by-step explanation:

just add 7 in.

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Find the area of the parallelogram with a base of 471.5 cm and height of 21.3 cm.

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4 years ago

A triangle is placed in a semicircle with a radius of 3 yd, as shown below. Find the area of the shaded region.

Kitty [74]

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Considering that the shaded area is the part of the semi circle outside the triangle:

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3 years ago

What are the magnitude and direction of u+v+w ?

nevsk [136]

The magnitude and the direction of the resultant are approximately 57.871 and 198.676°.

<h3>How to determine the magnitude and the direction of a resultant</h3>

Vectors are elements with two given characteristics: Magnitude and direction. A resultant is derived from the sum of vectors, the magnitude is the norm of a vector and the direction is the orientation of a vector. The resultant and its characteristics are described below:

<h3>Resultant</h3>

$\vec r = \left(\sum\limits_{i=1}^{n}x_{i}, \sum\limits_{i=1}^{n}y_{i}\right)$ (1)

<h3>Magnitude</h3>

$\|\vec r\| = \sqrt{\left(\sum\limits_{i=1}^{n} x_{i}\right)^{2}+\left(\sum\limits_{i=1}^{n} y_{i}\right)^{2}}$ (2)

<h3>Direction</h3>

$\theta = \tan^{-1}\frac{\sum\limits_{i=1}^{n}y_{i}}{\sum\limits_{i=1}^{n}x_{i}}$ (3)

Where $\theta$ is resultant angle, measured in degrees.

If we know that $\|\vec u\| = 90$ , $\theta_{u} = 40^{\circ}$ , $\|\vec v\| = 60$ , $\theta_{v} = 20^{\circ}$ , $\|\vec w\| = 40$ and $\theta_{w} = 30^{\circ}$ , then the resultant, its magnitude and its direction:

<h3>Resultant</h3>

$\vec r = (-90\cdot \cos 40^{\circ}-60\cdot \sin 20^{\circ}+40\cdot \cos 30^{\circ}, 40\cdot \sin 30^{\circ}+60\cdot \cos 20^{\circ}-90\cdot \sin 40^{\circ})$

$\vec r = (-54.824, 18.531)$

<h3>Magnitude</h3>

$\|\vec r\| = \sqrt{(-54.824)^{2}+18.531^{2}}$

$\|\vec r\| \approx 57.871$

<h3>Direction</h3>

$\theta = \tan^{-1} \left(\frac{18.531}{-54.824}\right)$

$\theta \approx 198.676^{\circ}$

The magnitude and the direction of the resultant are approximately 57.871 and 198.676°. $\blacksquare$

To learn more on vectors, we kindly invite to check this verified question: brainly.com/question/13322477

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2 years ago