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PilotLPTM [1.2K]
2 years ago
7

7. The lifetime of a certain brand of tires is approximately normally distributed, with a

Mathematics
1 answer:
Aleonysh [2.5K]2 years ago
7 0

Answer:

0.0025551

Step-by-step explanation:

Given that:

Mean (m) = 40000

Standard deviation (s) = 2500

P(x < 33,000) :

USing the relation to obtain the standardized score (Z) :

Z = (x - m) / s

Z = (33000 - 40000) / 2500 = - 2.8

p(Z < -2.8) = 0.0025551 ( Z probability calculator)

Probability of Tyre wagering out before mileage limit is reached = 0.0025551

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Answer:

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Step-by-step explanation:

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x_{i+1} = x_{i} -\frac{f(x_{i})}{f'(x_{i})}

Where:

x_{i} - i-th Approximation, dimensionless.

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f(x_{i}) - Function evaluated at i-th Approximation, dimensionless.

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x_{3} = 2 - \frac{1}{6}

x_{3} = \frac{11}{6}

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3 years ago
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Step-by-step explanation:

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Answer:

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