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34kurt
3 years ago
7

Create a set of coordinates to model a relation that is linear function.

Mathematics
1 answer:
weqwewe [10]3 years ago
3 0

Answer:

Step-by-step explanation:

The following points (coordinates) lie on a straight line with slope 3:

(1, 0), (2, 3), (3, 6), (4, 9) ... and so on

So the linear function is y = 3x + b, where b is the y-intercept.

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What is the resistance of a 3.1 m length of copper wire 1.7 mm in diameter?
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R = ?
L = 3.1 m;
r = 1.7 mm/ 2 = 0.85 mm = 0.85 * 10^(-3) m
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Complete the steps for deriving the quadratic formula using the following equation.
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Having obtained:

x^2+ \frac{b}{a}x+( \frac{b}{2a} )^2+ \frac{c}{a}-( \frac{b}{2a} )^2=0

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We have:

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(x+\frac{b}{2a} )^2=\frac{b^2-4ac}{4a^2}.


Next, we take the square root of both sides, which has been shown in the solution.


Next, we have to take b/2a to the right hand side as -(b/2a), and removing the square in the denominator of the right hand side expression:

x=-\frac{b}{2a}\pm \frac{\sqrt{b^2-4ac}}{2a}}.



Answer: the steps to complete in the boxes are :

 
(x+\frac{b}{2a} )^2+( \frac{4ac}{4a^2}-\frac{b^2}{4a^2} )=0.

(x+\frac{b}{2a} )^2=\frac{b^2-4ac}{4a^2}.

x=-\frac{b}{2a}\pm \frac{\sqrt{b^2-4ac}}{2a}}.

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