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ipn [44]
3 years ago
9

Can someone please help me with 1 and 2 :)

Mathematics
1 answer:
raketka [301]3 years ago
3 0

Answer:

1. {(2, 7), (1, 3), (0, -5), (-1, -2)}

2. {(1, -1), (-1, 0), (-3, -5), (-9, 2)}

Step-by-step explanation:

Inverse means finding the opposite so basically all you have to do is write the opposite of lets say -3 which is +3.

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How do I make this bell curve
Zanzabum

The mean you found is correct, but the standard deviation is not. Recall that the standard deviation \sigma_s (s for sample) of n points is given by

\sigma_s=\sqrt{\dfrac1{n-1}\displaystyle\sum_{1\le i\le n}(x_i-\bar x)^2}

where n=10 is the sample size, \bar x=3740 is the sample mean, and x_i are the prices listed in the circled column. So

\sigma_s=\sqrt{\dfrac{(3640-3740)^2+(7595-3740)^2+\cdots+(3390-3740)^2}{10-1}}

\implies\sigma_s\approx1443.98\approx1444

I can't tell if you need to provide any more info beyond this, but given there's a plot of a generalized bell curve, I think you're also supposed to label the plot.

At the center of the bell-shaped/normal distribution is the mean. Notice there are three tick marks to either side of the mean - these are probably supposed to represent prices that fall exactly 1, 2, and 3 standard deviations from the mean. These are, from left to right,

\bar x-3\sigma_s\approx3740-3(1444)=-592

\bar x-2\sigma_s\approx3740-2(1444)=852

\bar x-\sigma_s\approx2296

\bar x+\sigma_s\approx5184

\bar x+2\sigma_s\approx6628

\bar x+3\sigma_s\approx8072

8 0
3 years ago
What is CA in the figure
Snowcat [4.5K]

Answer:

The answer is D good luck :)

8 0
4 years ago
In a random sample of 625 people, it was found that 225 of them frequently check their work email when they are at home. Find th
VMariaS [17]

Answer: (0.3224,0.3976)

Step-by-step explanation:

Given : Sample size : n=625

Number of people check their work email when they are at home =225

The probability of people check their work email when they are at home :p=\dfrac{225}{625}=0.36

Significance level : \alpha:1-0.95=0.05

Critical value : z_{\alpha/2}=1.96

The confidence interval for population proportion is given by :-

p \pm z_{\alpha/2}\sqrt{\dfrac{p(1-p)}{n}}\\\\=0.36\pm(1.96)\sqrt{\dfrac{0.36(1-0.36)}{625}}\\\\=0.36\pm0.037632\\\\=(0.322368,0.397632)\approx(0.3224,0.3976)

4 0
3 years ago
Find the area of an equilateral triangle (regular 3-gon) with the given measurement.
Delicious77 [7]
I think it is 45.5. 1/2 base*height. (9*9 = 81. 81/2 = 45.5.
7 0
4 years ago
Read 2 more answers
Please explain & answer!!!!
zheka24 [161]
⌊x⌋ floors the input x. It will always round x down to the an integer that is lower.
Then that is multiplied by 4.
This results in
                                      g(5.7) = 4⌊5.7⌋ 
                                      g(5.7) = 4 * 5
                                      g(5.7) = 20
The answer to this question is 20.
3 0
3 years ago
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