Answer:
Step-by-step:
51⁷-51⁶ = 51⁶(51-1) = 51⁶(50)
50 is divisible by 25, so 51⁷-51⁶ is divisible by 25.
New annual renter's insurance premium = 325(1 + 0.18) = 325 x 1.18 = $383.50
The tangent or tanθ in a right-angle triangle is the ratio of its perpendicular to its base. The distance from point C to point D is 258.8 meters.
<h3>What is Tangent (Tanθ)?</h3>
The tangent or tanθ in a right-angle triangle is the ratio of its perpendicular to its base. it is given as,

where,
θ is the angle,
Perpendicular is the side of the triangle opposite to the angle θ,
The base is the adjacent smaller side of the angle θ.
The distance from point C to D is equal to the distance from point A to B. Therefore, the height of the building can be written as,
Tan(25°) = AB / BC
Tan(25°) × 555 m = AB
AB = 258.8 meters
Hence, the distance from point C to point D is 258.8 meters.
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Option D:
The approximate area of the figure is 109.6 square feet.
Solution:
The figure is splitted into three shapes.
One is rectangle and the other two is semi-circles.
Diameter of the semi-circle = 5 feet
Radius of the semi-circle = 5 ÷ 2 = 2.5 feet
Area of the semi-circle = 

Area of the semi-circle = 9.8 square feet
Area of 2 semi-circles = 2 × 9.8
Area of 2 semi-circles = 19.6 square feet
Length of the rectangle = 18 feet
Width of the rectangle = 5 feet
Area of the rectangle = length × width
= 18 × 5
Area of the rectangle = 90 square feet
Area of the figure = Area of 2 semi-circles + Area of the rectangle
= 19.6 square feet + 90 square feet
= 109.6 square feet
The approximate area of the figure is 109.6 square feet.
Hence Option D is the correct answer.
Answer:
The acceleration of the train is 0.5m/s²
Step-by-step explanation:
Given
Velocity of the train = 10m/s
Time taken = 20 s
Required
Find the acceleration of the train.
The Acceleration if an object is the rate of change of the velocity of the object over time.
In other words, acceleration is calculated by dividing velocity by time.
Mathematically,
Acceleration = velocity ÷ Time
By substituting 10m/s for velocity and 20s for time, we have
Acceleration = 10m/s ÷ 20s
Acceleration = 10/20 m/s²
Acceleration = ½m/s²
Acceleration = 0.5m/s²
Hence, the acceleration of the train is 0.5m/s²