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3 years ago

Nvm thanks anywaysssss

Mathematics

2 answers:

Elis [28]3 years ago

7 0

Answer:

ok.. I'll just take the points thanks <3

Step-by-step explanation:

kondor19780726 [428]3 years ago

6 0

Okayyy no problemmmm have a good day

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HELP PLEASE ASAP

Pie

$\bold{\huge{\underline{ Solution }}}$

We have, 

Line segment AB
The coordinates of the midpoint of line segment AB is ( -8 , 8 )
Coordinates of one of the end point of the line segment is (-2,20)

Let the coordinates of the end point of the line segment AB be ( x1 , y1 ) and (x2 , y2)

Also, 

Let the coordinates of midpoint of the line segment AB be ( x, y)

We know that,

For finding the midpoints of line segment we use formula :-

$\bold{\purple{ M( x, y) = }}{\bold{\purple{\dfrac{(x1 +x2)}{2}}}}{\bold{\purple{,}}}{\bold{\purple{\dfrac{(y1 + y2)}{2}}}}$

According to the question,

The coordinates of midpoint and one of the end point of line segment AB are ( -8,8) and (-2,-20) .

For x coordinates :-

$\sf{ -8 = }{\sf{\dfrac{(- 2 +x2)}{2}}}$

$\sf{2}{\sf{\times{ -8 = - 2 + x2 }}}$

$\sf{ - 16 = - 2 + x2 }$

$\sf{ x2 = -16 + 2 }$

$\bold{ x2 = -14 }$

For y coordinates :-

$\sf{ 8 = }{\sf{\dfrac{(- 20 +x2)}{2}}}$

$\sf{2}{\sf{\times{ 8 = - 20 + x2 }}}$

$\sf{ 16 = - 20 + x2 }$

$\sf{ y2 = 16 + 20 }$

$\bold{ y2 = 36 }$

Thus, The coordinates of another end points of line segment AB is ( -14 , 36)

Hence, Option A is correct answer

7 0

3 years ago

Owen took a total of 24 quizzes over the course of 6 weeks. How many weeks of school will Owen have to attend this quarter befor

kirill [66]

Since he got 24 quizes in 6 weeks that means he gets 4 every week
24/6=4
so what is 32/4=?
32/4=8
the answer is 8

7 0

3 years ago

Read 2 more answers

How many complex zeros does the polynomial function have? F(x)=2x^4 +5x^3 - x^2 +6x-1

klio [65]

Answer:

Two complex roots.

Step-by-step explanation:

F(x)=2x^4 +5x^3 - x^2 +6x-1

is a polynomial in x of degree 4.

Hence F(x) has 4 roots. There can be 0 or 2 or 4 complex roots to this polynomial since complex roots occur in conjugate pairs.

Use remainder theorem to find the roots of the polynomial.

F(0) = -1 and F(1) = 2+5-1+6-1 = 11>0

There is a change of sign in F from 0 to 1

Thus there is a real root between 0 and 1.

Similarly by trial and error let us find other real root.

F(-3) = -1 and F(-4) = 94

SInce there is a change of sign, from -4 to -3 there exists a real root between -3 and -4.

Other two roots are complex roots since no other place F changes its sign

7 0

3 years ago

Please answer !! what is the factorization of the trinomial below ?

Alex_Xolod [135]

Since we always want to have an a which equals 1 so then we don't have to do AC method, a longer process, we're going to want to take out the -1.

-1(x^2 - x - 42)

Then, we want to know what two number multiply to equal c (-42 here) and add up to equal b (-1 here). Those two numbers would be -7 and 6 since -7(6) = -42 and -7 + 6= -1.

So then from here we can just plop these numbers into (x+ __).

1(x-7)(x+6)

This is your final answer, A.

4 0

3 years ago

The probability of getting a number divisible by 3 is 3/10 using a game spinner.

lukranit [14]

Answer:

Step-by-step explanation:

the denominator should be the total amount of outcomes.

8 0

4 years ago