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FinnZ [79.3K]
3 years ago
7

Please help I would really Appreciate it so much ​

Mathematics
2 answers:
Mariulka [41]3 years ago
5 0

Answer:

the answer is 15a+12ac+6ab

Step-by-step explanation:

3a(5+4c+2b)

(3a)(5+4c+2b)

(3a)(5)+(3a)(4c)+(3a)(2b)

15a+12ac+6ab

6ab+12ac+15a

hope this helps!

expeople1 [14]3 years ago
4 0

Answer:

I think it is b

Step-by-step explanation:

it is 3a times all of the numbers in parenthases

hope you pass your test

HAPPY NEW YEAR

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Answer is D.
x = 0 and x = 4

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3 years ago
Which sets of measurements could be the side lengths of a triangle?
Varvara68 [4.7K]

Answer:

A

Step-by-step explanation:

easy way to take a note

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4 0
2 years ago
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The difference of 2 squared numbers equals 53, what are the numbers​
Eva8 [605]

Answer:

  27, 26

Step-by-step explanation:

  27^2 -26^2 = 729 -676 = 53

If the numbers are integers, they must differ by an odd number. For some odd number k, we will have ...

  (x +k)^2 -x^2 = 53

  2xk +k^2 = 53

  x = (53 -k^2)/(2k)

  x = 53/(2k) -k/2

The second term is an odd multiple of 1/2. The first term will be an odd multiple of 1/2 only for k=1. For k = 1, we have ...

  x = (53 -1)/2 = 26

The two numbers are 26 and 27.

8 0
3 years ago
Can someone plz help me with this math problem.
galben [10]
For question one, you would need to use the formula pi r ^2. So first you have 4.5, which is your radius(stands for r). Then you square it, which is 20.25. Then, you multiply 20.25 with pi. Then for circumference, you do 2 x pi x the radius which is 4.5. So for area, you get 63.62. Then for circumference you get 28.27. 

For question 2, it is basically the same steps but instead you a diameter, not a radius. To get the radius, divide by 2, which the radius will be 6. Then from there, the radius is 6, and you solve the question.
4 0
3 years ago
Read 2 more answers
Which of the following correctly describes the domain of the function shown
labwork [276]

Option D:

\{x: x \neq 1\} is the domain of the function.

Solution:

Given function is

$r(x)=\frac{2 x}{x-1}

<u>To find the domain of the function:</u>

Option A: \{x: x \neq 0\}

Substitute x = 0 in r(x).

$r(0)=\frac{2 \times 0}{0-1}=0

If x = 0, then r(0) = 0

So that x ≠ 0 is false.

So, \{x: x \neq 0\} is not the domain of the function.

Option B: \{x: x \neq \pm 1\}

Substitute x = –1 in r(x).

$r(-1)=\frac{2 \times (-1)}{-1-1}=1

If x = –1, then r(–1) = 1

So that x = ± 1 is false.

So, \{x: x \neq \pm 1\} is not the domain of the function.

Option C: $\{x: \text { all real numbers }\}$

Substitute x = 1 in r(x).

$r(1)=\frac{2 \times 1}{1-1}=\frac{2}{0}

It is indeterminate.

So, all real numbers are not the domain of the function.

Option D: \{x: x \neq 1\}

Substitute x = 1 in r(x).

$r(1)=\frac{2 \times 1}{1-1}=\frac{2}{0}

It is indeterminate.

So, \{x: x \neq 1\} is the domain of the function.

4 0
3 years ago
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