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masya89 [10]
3 years ago
10

What is the vertex of y=-3x^2 4?

Mathematics
1 answer:
Ket [755]3 years ago
6 0
The answer to the question is y=-24x
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What is the 72nd term of -27, -11, 5
FinnZ [79.3K]

Answer:

1109

Step-by-step explanation:

The first term is -27, and the common difference is 16.

The nth term is:

a = a₁ + d (n − 1)

a = -27 + 16 (n − 1)

a = -27 + 16n − 16

a = 16n − 43

The 72nd term is:

a = 16(72) − 43

a = 1109

5 0
3 years ago
Consider a cylinder with a diameter of 8 feet and a height of h feet. Which equation can be used to find V, the volume of the cy
Arlecino [84]

Answer:

The correct answer is option A

Step-by-step explanation:

The volume of a cylinder is given by

V = \pi r^{2} h\\

Substituting the values of radius and height in above equation, we get -

radius = \frac{diameter}{2} \\radius = \frac{8}{2} \\radius = 4 feet\\V = \pi 4^{2} h\\

5 0
4 years ago
Read 2 more answers
The prime factorizations of 54 and 72 are shown below.
Karo-lina-s [1.5K]
Your answer is 2’3’3!! (2*3*3 = 18)

hopefully this helps, good luck bud! :)

5 0
3 years ago
Read 2 more answers
What is 4.12 rounded to the nearest tenth
Gnom [1K]
4.12 rounded to the nearest tenth is 4.1
8 0
3 years ago
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The differential equation y′′=0 has one of the following two parameter families as its general solution: yyyy=C1ex+C2e−x=C1cos(x
svet-max [94.6K]

Answer:

y_c = 2 + 10*x

Step-by-step explanation:

Given:

                                                y'' = 0

Find:

- The solution to ODE such that y(0) = 2, y'(0) = 10

Solution:

- Assuming a solution y = Ce^(mt)

So,                                y' = C*me^(mt)

                                    y'' = C*m^2e^(mt)

- Back substitute into given ODE, we get:

                                    y'' = C*m^2e^(mt) = 0

                                    e^(mt) can not be equal to zero

- Hence,                       m^2 = 0

                                     m = 0 , 0 - (repeated roots)

- The complimentary function for repeated roots is:

                                    y_c = (C1 + C2*x)*e^(m*t)

                                    y_c = C1 + C2*x  

- Evaluate @ y(0) = 2

                                    2 = C1 + C2*0

                                    C1 = 2

-Evaluate @ y'(0) = 10

                                    y'(t) = C2 = 10

Hence,                         y_c = 2 + 10*x

5 0
3 years ago
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