Solve the equation. 2/3 t=4/5
1 answer:
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Answer:
p(x) = 0.1x + 1
Step-by-step explanation:
Pressure at sea level = 1 atmosphere
Depth dove by Sydney = 23 meters
Pressure at a depth of 23 meters = 3.3 atmospheres
So,
Pressure at a depth of 23 meters = Pressure at sea level + k * Depth dove by Sydney
where k is the diving rate constant
=> 3.3 = 1 + k(23)
=> 3.3 = 23k + 1
Subtracting 1 from both the sides, we get
3.3 - 1 = 23k + 1 -1
Cancelling out the +1 and -1 from the right side, we get
2.3 = 23k
=> 23k = 2.3
Dividing both sides by 23, we get
Cancelling out the 23's from the top and bottom of the left side, we have
k = 0.1
Plugging in the value of k in the equation, we get
Pressure at a particular depth = Pressure at sea level + k * Depth dove by Sydney
p(x) = 1 + k(x) [where p(x) is the pressure at a depth x]
=> p(x) = 1 + 0.1(x)
=> p(x) = 0.1x + 1
The value of this expression is
In order to find this, you divide each term separately. First we'll start with the numbers in the front.
Now that we have the first number, we look to the 10s and the powers they are raised to. Since we are looking at powers of the same number, we can use the properties of exponents to simply subtract the numbers they are raised to.
Then we put the two back together for the final answer.
The answer is 192.2.....
is continues on forever
Hope this helps!
is continues on forever
Hope this helps!