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REY [17]
3 years ago
12

Determine the empirical formula of an oxide of silicon from the following: mass of crucible= 18.20g, mass of crucible +silicon =

18.48g and mass of crucibe+ oxide of silicon =18.80g​
Chemistry
1 answer:
lyudmila [28]3 years ago
4 0
The required empirical formula of the silicon oxide is SiO2.
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How does increasing the temperature affect a reaction?
Luden [163]

Answer:A. An increase in temperature increases the reaction rate.

Explanation:because of the disproportionately large increase in the number of high energy collisions. It is only these collisions (possessing at least the activation energy for the reaction) which result in a reaction.

4 0
3 years ago
Why sometimes the electrons of an atom transfer to higher energy level​
Elenna [48]

Answer:

According to Bohr, the amount of energy needed to move an electron from one zone to another is a fixed, finite amount. ... The electron with its extra packet of energy becomes excited, and promptly moves out of its lower energy level and takes up a position in a higher energy level. This situation is unstable, however.

8 0
3 years ago
Different measurements are expressed in different units. Choose the correct Sl units for the lo
swat32

Answer:

The SI units for measuring the velocity of the car: meters per second (m/s)

The Sl units for measuring the acceleration of the car: meters per second squared  (m/s^2)

The SI units for measuring force:  Newton (N)

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Explanation:

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8 0
3 years ago
What is the mole to mole relationship between copper and zinc? Cu2+(aq)+->Cu(s)+Zn2+(aq)
Aliun [14]

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5 0
4 years ago
Calculate the mass of ethyl alcohol required to prepare 540 grams of C4H6, if the reaction follows the scheme:
kkurt [141]

Answer:

Explanation:

2C₂H₅OH    =   C₄H₆  +  2H₂O  +  H₂

2 mole               1 mole

molecular weight of ethyl alcohol

mol weight of C₂H₅OH = 46 gm            

mol weight of C₄H₆  54 gm

540 gm of C₄H₆ = 10 mole

10 mole of C₄H₆ will require 20 mol of ethyl alcohol .

20 mole of ethyl alcohol = 20  x 46

= 920 gm

ethyl alcohol required = 920 gm .

3 0
3 years ago
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