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REY [17]
2 years ago
12

Determine the empirical formula of an oxide of silicon from the following: mass of crucible= 18.20g, mass of crucible +silicon =

18.48g and mass of crucibe+ oxide of silicon =18.80g​
Chemistry
1 answer:
lyudmila [28]2 years ago
4 0
The required empirical formula of the silicon oxide is SiO2.
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What mass of hydrogen contains the same number of atoms as 7.00 g of nitrogen
Leto [7]
Molecular mass of nitrogen, N2 = 2*14 = 28
molecular mass of hydrogen, H2=2*1 = 2

Molecules of both elements contain 2 atoms, so the ratio of molecules is the same as the ratio of atoms.

From the molecular masses above, 
ratio of number of molecules = ratio of molecular masses, therefore
7g N2 : x g H2 = 28:2
cross multiply:
x=7*2/28=0.5 g of Hydrogen has the same number of atoms as 7 g of nitrogen (at room temperatures)

7 0
2 years ago
Based upon the mass of baking soda (NaHCO3) and using an excess of HCl in this experiment, you will 1) determine the mass of CO2
weqwewe [10]

Equation of reaction

NaHCO3 +  HCl  --------->  NaCl  +  H2O  +  CO2(g)

1)The mass(actual yield) of CO2 can be gotten by isolating it from other products and getting its mass.

Assume 1.0g of CO2 was gotten as a product of the experiment

2) For the theoretical yield

The mass of NaHCO3 was not stated, but for the purpose of this solution, I would assume 2g of NaHCO3 was used for the experiment. You can substitute any parameter by following the steps I follow

Number of mole of NaHCO3 = Mass of NaHCO3/ Molar Mass of NaHCO3

Number of mole of NaHCO3 = 2/84.01 = 0.0238 moles

1 mole of NaHCO3 yielded 1 mole of CO2

0.0238 moles of NaHCO3 will yield 0.0238 moles of CO2

Mass of CO2 = Number of moles * Molar Mass

Mass of CO2 = 0.0238 * 44 = 1.0472g

Theoretical yield of CO2 = 1.0472 grams

3) Percentage yield of CO2 = Actual yield/Theoretical yield *100%

Percentage yield of CO2 = 1.0/1.0472 *100

Percentage yield of CO2 = 95.49%

8 0
3 years ago
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What is the volume of 1g of ice in cm3?
Amanda [17]

Answer:

What is the volume of 1g of ice in cm3?

What is the volume of 1g of ice in cm3?

What is the volume of 1g of ice in cm3?

What is the volume of 1g of ice in cm3?

What is the volume of 1g of ice in cm3?

What is the volume of 1g of ice in cm3?

What is the volume of 1g of ice in cm3?

What is the volume of 1g of ice in cm3?

What is the volume of 1g of ice in cm3?

What is the volume of 1g of ice in cm3?

What is the volume of 1g of ice in cm3?

What is the volume of 1g of ice in cm3?

What is the volume of 1g of ice in cm3?

What is the volume of 1g of ice in cm3?

What is the volume of 1g of ice in cm3?

What is the volume of 1g of ice in cm3?

What is the volume of 1g of ice in cm3?

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What is the volume of 1g of ice in cm3?

What is the volume of 1g of ice in cm3?

What is the volume of 1g of ice in cm3?

What is the volume of 1g of ice in cm3?

What is the volume of 1g of ice in cm3?

What is the volume of 1g of ice in cm3?

What is the volume of 1g of ice in cm3?

What is the volume of 1g of ice in cm3?

What is the volume of 1g of ice in cm3?

What is the volume of 1g of ice in cm3?

What is the volume of 1g of ice in cm3?

What is the volume of 1g of ice in cm3?

What is the volume of 1g of ice in cm3?

What is the volume of 1g of ice in cm3?

What is the volume of 1g of ice in cm3?

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What is the volume of 1g of ice in cm3?

What is the volume of 1g of ice in cm3?

What is the volume of 1g of ice in cm3?

What is the volume of 1g of ice in cm3?

What is the volume of 1g of ice in cm3?

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Explanation:

3 0
3 years ago
How many protons are present in one copper(ii) ion?
AlladinOne [14]
Copper has 29 protons, when dealing with Cu^2+ all that means is it lost two electrons. so now the element has 29 protons and 27 electrons. Protons are positive and electrons are negative and neutrons are neutral. So say you had an element X^2- then you have gained two more electrons so the element has an overall negative charge. hope that helps


6 0
3 years ago
What are the equilibrium concentrations of pb2+ and f– in a saturated solution of lead(ii) fluoride if the ksp of pbf2 is 3.20×1
erica [24]
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Ksp = 3,2·10</span>⁻⁸.
[Pb²⁺] = x.
[F⁻] = 2[Pb²⁺] = 2x<span>
Ksp = [Pb²</span>⁺] · [F⁻]².
Ksp = x · 4x².
3,2·10⁻⁸ = 4x³.
x = ∛3,2·10⁻⁸ ÷ 4.
x = [Pb²⁺] = 0,002M = 2·10⁻³ M.
[F⁻] = 2 · 0,002M = 0,004 M = 4·10⁻³ M.

6 0
3 years ago
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