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ioda
2 years ago
5

What charge would you expect for an formed by S?

Chemistry
1 answer:
sp2606 [1]2 years ago
6 0

Answer:

in this the correct answer is option 2.

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A medium can be anything that a wave can pass through e.g the medium can be solid objects, air, water, etc.
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A 10.0 ml portion of 0.010 m hcl is diluted by adding it to100.0 ml of water. what is the ph of the solution
Volgvan

From the calculation, the pH of the solution after dilution is 3.

<h3>What is the pH?</h3>

The pH is the hydrogen ion concentration of the solution. Now we know that;

C1 =  0.010 m

V1 = 10.0 ml

V2 = 10.0 ml + 100.0 ml = 110 ml

C2 = ?

C1V1 = C2V2

C2 = C1V1 /V2

C2 =  0.010 m  * 10.0 ml / 110 ml

C2 = 0.00091 M

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4 0
2 years ago
Which of the following factors affects the strength of the gravitational force between two objects?
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D. the distance between the objects
6 0
3 years ago
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Necesito saber esto porfavor, ¿ cuales son las ventajas que representan los espectroscopia en cuanto al estudio de los elementos
igomit [66]

Answer:

Por favor,no ponga exactamente lo que pongo,Trate de parafrasear.

La espectroscopia es el estudio de la interacción entre la materia y la radiación electromagnética en función de la longitud de onda o frecuencia de la radiación. La espectroscopia puede ser muy útil para ayudar a los científicos a comprender cómo un objeto como un agujero negro, una estrella de neutrones o una galaxia activa produce luz, qué tan rápido se mueve y de qué elementos está compuesto. Se pueden producir espectros para cualquier energía de la luz, desde ondas de radio de baja energía hasta rayos gamma de muy alta energía.

Responde a esta pregunta?

5 0
2 years ago
A sample of 28 Mg decays initially at a rate of 53500 disintegrations per minute, but the decay rate falls to 10980 disintegrati
prisoha [69]

Answer : The half life of 28-Mg in hours is, 6.94

Explanation :

First we have to calculate the rate constant.

Expression for rate law for first order kinetics is given by:

k=\frac{2.303}{t}\log\frac{a}{a-x}

where,

k = rate constant

t = time passed by the sample = 48.0 hr

a = initial amount of the reactant disintegrate = 53500

a - x = amount left after decay process disintegrate = 53500 - 10980 = 42520

Now put all the given values in above equation, we get

k=\frac{2.303}{48.0}\log\frac{53500}{42520}

k=9.98\times 10^{-2}hr^{-1}

Now we have to calculate the half-life.

k=\frac{0.693}{t_{1/2}}

9.98\times 10^{-2}=\frac{0.693}{t_{1/2}}

t_{1/2}=6.94hr

Therefore, the half life of 28-Mg in hours is, 6.94

8 0
3 years ago
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