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Levart [38]
3 years ago
5

You have a gas at a pressure of 5 atm and a temperature of 300 K, what is the new pressure if the temperature is decreased to 20

0 K?
Chemistry
1 answer:
lesya [120]3 years ago
4 0

Answer:

3.33 atm

Explanation:

P1/T1 = P2/T2

5 atm/ 300 K = P2 /200K

P2 = 5atm*200 K/300 K

P2 = 3.33 atm

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Double replacement i believe
6 0
3 years ago
How far is Louisville from the nearest oil field?​
rjkz [21]

Answer:

anyywhere between 20-23 miles

Explanation:

it depends what type of oil field u mean

7 0
3 years ago
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If the pressure changes from 1 atm to 3 atm, what does the volume of 30 L change to
DiKsa [7]

Answer: 10L

Explanation:

Given that:

Initial pressure P1 = 1 atm

New pressure P2 = 3 atm

Initial volume V2 = 30 L

New volume V2 = ?

Since pressure and volume are involved, apply the formula for Boyle's law

P1V1 = P2V2

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5 0
3 years ago
In the following reaction, which substance is the precipitate? (NH4)2SO4(aq) + Ba(NO3)2(aq) BaSO4(s) + 2NH4NO3(aq
mariarad [96]
Assuming that the reactants are:

(NH4)2SO4 (aq) + Ba(NO3)2 (aq)

and the products are:

BaSO4 (s) + 2NH4NO3 (aq),

then you will have to determine which product is insoluble. You should have access to solubility rules to help you determine this.

According to the solubility rules, the following elements are considered insoluble when paired with SO4:

Sr^2+, Ba^2+, Pb^2+, Ag^2+, and Ca^2+

Therefore, the precipitate will be BaSO4 (s).

5 0
3 years ago
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According to VSEPR theory, a molecule with the general formula AX2E2 (A is the central atom, X is the bonded atom and E is a lon
ratelena [41]

Answer:

see explanation

Explanation:

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4 0
3 years ago
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