Explanation:
A manometer is a device that measures air pressure using a container with a "U"-shaped tube open at one or both ends. In a closed manometer, a sample of gas is introduced into one end, which is then capped. ... This pressure represents the positive or negative difference between the gas pressure and atmospheric pressure
The momentum of two or more objects during collisions is not lost nor gained
Density is mass divided by volume p=m/v
Answer:
<em>The ball missed the basket by 1.6 meters</em>
Explanation:
<u>Projectile Motion
</u>
It's when an object is moving in a two-dimensional space, being thrown with an initial speed and angle respect to the horizontal direction. The horizontal distance traveled by the object is given by
![x=vo.cos\theta .t](https://tex.z-dn.net/?f=x%3Dvo.cos%5Ctheta%20.t)
And the vertical height above the level of the launch is
![\displaystyle y=vo.sin\theta. t-\frac{gt^2}{2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20y%3Dvo.sin%5Ctheta.%20t-%5Cfrac%7Bgt%5E2%7D%7B2%7D)
The basketball player throws the ball with initial speed
at an angle of
. The horizontal distance to the basket (as suggested by the 'downrange' word) is x=6.1 m. We need to find out if the ball reaches the basket at a height y=1.2 m above the launching point.
From the equation
![x=vo.cos\theta .t](https://tex.z-dn.net/?f=x%3Dvo.cos%5Ctheta%20.t)
We'll solve for t and find the flight time until the horizontal distance is reached by the ball
![\displaystyle t=\frac{x}{vo.cos\theta}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20t%3D%5Cfrac%7Bx%7D%7Bvo.cos%5Ctheta%7D)
![\displaystyle t=\frac{6.1}{(7.8).cos55^o}=1.363\ sec](https://tex.z-dn.net/?f=%5Cdisplaystyle%20t%3D%5Cfrac%7B6.1%7D%7B%287.8%29.cos55%5Eo%7D%3D1.363%5C%20sec)
Now, we use this time to find y
![\displaystyle y=(7.8).sin55^o . (1.363)-\frac{(9.8)(1.363)^2}{2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20y%3D%287.8%29.sin55%5Eo%20.%20%281.363%29-%5Cfrac%7B%289.8%29%281.363%29%5E2%7D%7B2%7D)
![y=-0.4\ m](https://tex.z-dn.net/?f=y%3D-0.4%5C%20m)
The negative sign indicates the ball fell below the launching point, and missed the basket by
![1.2+0.4 = 1.6\ m](https://tex.z-dn.net/?f=1.2%2B0.4%20%3D%201.6%5C%20m)
If we use the equation:
N2 + 3H2 --> 2NH3
Then
1 mol of Nitrogen required 3 moles of Hydrogen
x mols : 6.34mols
X = 6.34/3
X = 2.11 moles of Nitrogen are required.