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Harman [31]
3 years ago
8

Need help with this, 10 points

Mathematics
1 answer:
Taya2010 [7]3 years ago
6 0

Answer:

A

Step-by-step explanation:

I did it in a on a piece of paper

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Refer to the various selling prices of various homes in a community that follow the normal distribution with mu (population mean
blsea [12.9K]

Answer:

0.43715

Step-by-step explanation:

We solve using z score calculator

z = (x-μ)/σ, where

x is the raw score

μ is the population mean = $276,000

σ is the population standard deviation = 32,000

For x = $276,000

z = 276,000 - 276,000/32000

z = 0

Probability value from Z-Table:

P(x = 276000) = 0.5

For x = $325,000

z = 325,000 - 276,000/32000

z = 1.53125

Probability value from Z-Table:

P(x = 325000) = 0.93715

The probability that the next house in the community will sell for between $276,000 and $325,000 is

P(x = 325000) - P(x = 276000)

= 0.93715 - 0.5

= 0.43715

8 0
3 years ago
Choose the fraction below that would make the following proportion true. 3/4 = ?/? A 1/2 B 4/5 C 6/8 or D 9/10
Daniel [21]

Answer:

C

Step-by-step explanation:

3/4 x 2/2= 6/8

6/8 = 6/8

5 0
3 years ago
Y = -5<br> 2x – 4y = 18<br> PLEASE HELP NO LINKS<br> LINKS=REPORT
Ber [7]

Answer:

x= -1

Step-by-step explanation:

since y is -5 then we would put that in the second equation:

2x - 4(-5) = 18

then it’s:

2x + 20 = 18

Then we subtract 20 from both sides

2x = -2

Last we divide both by 2 and we get x = -1

5 0
3 years ago
Read 2 more answers
What is the period and midline?
OverLord2011 [107]
\bf \qquad \qquad \qquad \qquad \textit{function transformations}&#10;\\ \quad \\&#10;% function transformations for trigonometric functions&#10;\begin{array}{rllll}&#10;% left side templates&#10;f(x)=&{{  A}}cos({{  B}}x+{{  C}})+{{  D}}&#10;\\ \quad \\&#10;&#10;\end{array}\qquad

\bf \begin{array}{llll}&#10;% right side info&#10;\bullet \textit{ stretches or shrinks}\\&#10;\quad \textit{horizontally by amplitude } |{{  A}}|\\&#10;\bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\&#10;\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\&#10;\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\&#10;\bullet \textit{vertical shift by }{{  D}}\\&#10;\qquad if\ {{  D}}\textit{ is negative, downwards}\\&#10;\qquad if\ {{  D}}\textit{ is positive, upwards}\\&#10;&#10;&#10;\end{array}

\bf \begin{array}{llll}&#10;\bullet \textit{function period}\\&#10;\qquad \frac{2\pi }{{{  B}}}\ for\ cos(\theta),\ sin(\theta),\ sec(\theta),\ csc(\theta)\\&#10;\qquad \frac{\pi }{{{  B}}}\ for\ tan(\theta),\ cot(\theta)&#10;\end{array}&#10;

so if you notice yours \bf \begin{array}{llll}&#10;3.2cos&\left( \frac{5}{3}\theta \right)+&6.1\\&#10;&\ \uparrow&\uparrow \\&#10;&B&D &#10;\end{array}

now.. normally the function \bf 3.2cos&\left( \frac{5}{3}\theta \right)
 has a D value of 0, or no vertical shift, and the amplitude and the period simply make the wave taller and thinner, but the midline is still the x-axis

now, with D = 6.1, that moves the midline  up vertically that much

now.. the period, well, B = 5/3, normal period of cosine is 2\pi
so, the new period will be \bf \cfrac{2\pi }{B}\implies \cfrac{2\pi }{\frac{5}{3}}\implies \cfrac{6\pi }{5}

notice the picture below
the vertical shift by the D component, or 6.1, moved the midline to y = 6.1 :)

6 0
3 years ago
ALGEBRA 1
Pavlova-9 [17]
It would be helpful if you could post a photo so I can look at the context. Thank you
4 0
3 years ago
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