Here's one way to do it.
AB ≅ AC . . . . . . . . . . given
∠BAY ≅ ∠CAY . . . . given
AY ≅ AY . . . . . . . . . . reflexive property
ΔBAY ≅ ΔCAY . . . .. SAS congruence
XY ≅ XY . . . . . . . . . . reflexive property
∠AYB ≅ ∠AYC . . . . CPCTC
BY ≅ CY . . . . . . . . . . CPCTC
ΔXYB ≅ ΔXYC . . . .. SAS congruence
Therefore ...
∠XCY ≅ ∠XBY . . . . CPCTC
Answer:
Step-by-step explanation:
15s-100=350
the last one
IDK if you need this s=30
Answer:
Step-by-step explanation:
Given
Required
Represent the width as an inequality
First, we represent the area as an inequality.
max as used above means less than or equal to.
So, we have:
The area of a rectangle is:
So, we have:
Substitute 10 for L
Divide both sides by 10
Answer:
OPTION B - 41
Step-by-step explanation:
An expression is given and the corresponding values for the expression are also given. We have to substitute the given values to arrive at the answer.
The given expression is: x + 3y + z.
Also given: x = 4, y = 5, z = 22.
Substitute these values in the above expression, we get:
4 + 3(5) + 22 = 4 + 15 + 22 = 41.
∴ x + 3y + z = 41
Yes this is the best kind of question
