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3 years ago

What are biofertilisiers

1 answer:

3 0

☆ Bio fertilizer :- Biofertilisers are organisms that enrich the nutrient quality of the soil. The main source f biofertilizers are bacteria, fungi and cyanobacteria.

HOPE IT HELPS ❣️

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A drawer contains 2 red shirts and 4 blue shirts. A second drawer contains 3 pairs of grey pants and 2 pairs of blue pants. A th

viktelen [127]

Answer:

b . may be

may it helped u ....

4 0

3 years ago

If the length of a rectangle is a two-digit number with identical digits and the width is 1/10 the length and the perimeter is 2

Oksanka [162]

If the length of a rectangle is a two-digit number with identical digits and the width is 1/10 the length and the perimeter is 2 times the area of the rectangle, what is the the length and the width

Solution:

Let the length of rectangle=x

Width of rectangle=x/10

Perimeter is 2(Length+Width)

= 2(x+x/10)

Area of Rectangle= Length* Width=x*x/10

As, Perimeter=2(Area)

So,2(x+x/10)=2(x*x/10)

Multiplying the equation with 10, we get,

2(10x+x)=2x²

Adding Like terms, 10x+x=11x

2(11x)=2x^2

22x=2x²

2x²-22x=0

2x(x-11)=0

By Zero Product property, either x=0

or, x-11=0

or, x=11

So, Width=x/10=11/10=1.1

Checking:

So, Perimeter=2(Length +Width)=2(11+1.1)=2*(12.1)=24.2

Area=Length*Width=11*1.1=12.1

Hence, Perimeter= 2 Area

As,24.2=2*12.1=24.2

So, Perimeter=2 Area

So, Answer:Length of Rectangle=11 units

Width of Rectangle=1.1 units

7 0

3 years ago

Read 2 more answers

The scores of students on the ACT college entrance exam in a recent year had the normal distribution with mean  =18.6 and stand

Maurinko [17]

Answer:

a) 33% probability that a single student randomly chosen from all those taking the test scores 21 or higher.

b) 0.39% probability that the mean score for 76 students randomly selected from all who took the test nationally is 20.4 or higher

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sample means with size n of at least 30 can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$

In this problem, we have that:

$\mu = 18.6, \sigma = 5.9$

a) What is the probability that a single student randomly chosen from all those taking the test scores 21 or higher?

This is 1 subtracted by the pvalue of Z when X = 21. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{21 - 18.6}{5.4}$

$Z = 0.44$

$Z = 0.44$ has a pvalue of 0.67

1 - 0.67 = 0.33

33% probability that a single student randomly chosen from all those taking the test scores 21 or higher.

b) The average score of the 76 students at Northside High who took the test was x =20.4. What is the probability that the mean score for 76 students randomly selected from all who took the test nationally is 20.4 or higher?

Now we have $n = 76, s = \frac{5.9}{\sqrt{76}} = 0.6768$

This probability is 1 subtracted by the pvalue of Z when X = 20.4. So

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{20.4 - 18.6}{0.6768}$

$Z = 2.66$

$Z = 2.66$ has a pvalue of 0.9961

1 - 0.9961 = 0.0039

0.39% probability that the mean score for 76 students randomly selected from all who took the test nationally is 20.4 or higher

4 0

3 years ago

I cant remember how to do this

Scrat [10]

Answer:

z = 80°

Step-by-step explanation:

ABCD ~ FECG

∠F ≅ ∠A = z

∠F = 360-100-60-120=80

z = 80°

3 0

3 years ago

How do I make the equation in slope intercept form for No. 4?

dezoksy [38]

Since the slope and the y-intercept for the equation of y = mx + b doesn't exist, you don't need to include it.

y = mx + b

Without the m and b, which are the slope and y-intercept, you are left with x.

Then, you need to figure out whether the line is horizontal, or vertical.

If the line is vertical, you keep the x, and find out the value x is on for every point of y.

If the line is horizontal, you keep the y, and find out the value y is on for every point of x.

Since the line is vertical, we can use x = ?

The line is always at x=2, no matter what the y-value is, so the final equation would be x=2.

<em>I hope this helped you! :)</em>

7 0

3 years ago

Read 2 more answers

What are biofertilisiers​

What are biofertilisiers