Find the area of the shaded region. 2 cm 2 cm 2 cm 2 cm 3 cm 2 cm 2 cm 2 cm 2 cm

Write the equation of the line that passes through the points

sesenic [268]

Answer:

$y+5=2(x-3)$ or $y+9=2(x-1)$

Step-by-step explanation:

step 1

Find the slope of the line

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

we have the ordered pairs

(3,-5) and (1,-9)

substitute the values

$m=\frac{-9+5}{1-3}$

$m=\frac{-4}{-2}$

$m=2$

step 2

Find the equation in point slope form

$y-y1=m(x-x1)$

Analyze two cases

First case

we have

$m=2$

$point\ (3,-5)$

substitute

$y+5=2(x-3)$

Second case

we have

$m=2$

$point\ (1,-9)$

substitute

$y+9=2(x-1)$

Note: The equation of the line in point slope form varies according to the point you choose, in contrast to the slope-intercept form

6 0

3 years ago

Insert parentheses to make each statement true -8+3-2+7=-16

quester [9]

this is the answer and where the parentheses -8+(3-2)+7=-16

8 0

3 years ago

Check if given set of numbers 6,8,10 forms pythagorean triplet or not?

kipiarov [429]

$\LARGE{ \underline{ \tt{Required \: answer:}}}$

We know that,

Pythagoras theoram is given by : p² + b² = h²

In a Pythagoras triplet, the longest side represents the hypotenuse of the triangle.

Then,

We should check that, whether the sum of squares of the smaller sides will be equal to the square of the third side or not. Then, we can determine the above easily.

Sum of squares of smaller sides:

= 6² + 8²

= 36 + 64

= 100

Square of longer side:

= 10²

= 100

Sum of squares of smaller sides = Square of longer side. Hence, 6,8,10 are Pythagorean triplets.

And we are done! :D

⛱️ $\large{ \blue{ \bf{FadedElla}}}$

6 0

2 years ago

For which system of equations is (5, 3) the solution? A. 3x – 2y = 9 3x + 2y = 14 B. x – y = –2 4x – 3y = 11 C. –2x – y = –13 x

Alla [95]

The correct answer is:

D) $\left \{ {{2x-y=7} \atop {2x+7y=31}} \right.$ .

Explanation:

We solve each system to find the correct answer.

For A:
$\left \{ {{3x-2y=9} \atop {3x+2y=14}} \right.$

Since we have the coefficients of both variables the same, we will use elimination to solve this.

Since the coefficients of y are -2 and 2, we can add the equations to solve, since -2+2=0 and cancels the y variable:
$\left \{ {{3x-2y=9} \atop {+(3x+2y=14)}} \right. 
\\
\\6x=23$

Next we divide both sides by 6:
6x/6 = 23/6
x = 23/6

This is not the x-coordinate of the answer we are looking for, so A is not correct.

For B:
$\left \{ {{x-y=-2} \atop {4x-3y=11}} \right.$

For this equation, it will be easier to isolate a variable and use substitution, since the coefficient of both x and y in the first equation is 1:
x-y=-2

Add y to both sides:
x-y+y=-2+y
x=-2+y

We now substitute this in place of x in the second equation:
4x-3y=11
4(-2+y)-3y=11

Using the distributive property, we have:
4(-2)+4(y)-3y=11
-8+4y-3y=11

Combining like terms, we have:
-8+y=11

Add 8 to each side:
-8+y+8=11+8
y=19

This is not the y-coordinate of the answer we're looking for, so B is not correct.

For C:
Since the coefficient of x in the second equation is 1, we will use substitution again.

x+2y=-11

To isolate x, subtract 2y from each side:
x+2y-2y=-11-2y
x=-11-2y

Now substitute this in place of x in the first equation:
-2x-y=-13
-2(-11-2y)-y=-13

Using the distributive property, we have:
-2(-11)-2(-2y)-y=-13
22+4y-y=-13

Combining like terms:
22+3y=-13

Subtract 22 from each side:
22+3y-22=-13-22
3y=-35

Divide both sides by 3:
3y/3 = -35/3
y = -35/3

This is not the y-coordinate of the answer we're looking for, so C is not correct.

For D:
Since the coefficients of x are the same in each equation, we will use elimination. We have 2x in each equation; to eliminate this, we will subtract, since 2x-2x=0:

$\left \{ {{2x-y=7} \atop {-(2x+7y=31)}} \right. 
\\
\\-8y=-24$

Divide both sides by -8:
-8y/-8 = -24/-8
y=3

The y-coordinate is correct; next we check the x-coordinate Substitute the value for y into the first equation:
2x-y=7
2x-3=7

Add 3 to each side:
2x-3+3=7+3
2x=10

Divide each side by 2:
2x/2=10/2
x=5

This gives us the x- and y-coordinate we need, so D is the correct answer.

7 0

3 years ago

the population of san san Pablo ca is about 33,950 people. ten years ago the population was about 30,000. by what PERCENT did th

azamat

Answer:

ABOUT 13 PERCENT

Step-by-step explanation:

I AM NOT CERTAIN BUT I GOT IT BY:

NEW PRICE - OLD PRICE divided by OLD PRICE X 100

5 0

3 years ago

Find the area of the shaded region. 2 cm 2 cm 2 cm 2 cm 3 cm 2 cm 2 cm 2 cm 2 cm​

Find the area of the shaded region. 2 cm 2 cm 2 cm 2 cm 3 cm 2 cm 2 cm 2 cm 2 cm