3/4 times 3/2 (reciprocal of the second fraction) is 9/8 gallons per minute.
5/8 times 2/1 (reciprocal of the second fraction) is 10/8 gallons per minute

The second tank is filling faster.

8 0

3 years ago

Read 2 more answers

Emmett participated in a race. During the race, he ran 5 miles north and then ran 12 miles west. What is the shortest distance t

Lelechka [254]

I'd suggest you sketch this situation. If you did, you'd likely see right away that the shortest distance back to the starting point would be the hypotenuse of the right triangle whose legs are of lengths 5 miles and 12 miles.

Apply the Pythagorean Theorem to solve this.

4 0

3 years ago

Eliot is simplifying a radical.<br><br><br> Please help it’s times

horrorfan [7]

It is the third answer down

4 0

3 years ago

Read 2 more answers

What are the coordinates of the endpoints of the midsegment for DEF that is parallel to DE

Nutka1998 [239]

Answer:

$\left(\dfrac{x_D+x_F}{2},\dfrac{y_D+y_F}{2}\right),$ $\left(\dfrac{x_E+x_F}{2},\dfrac{y_E+y_F}{2}\right).$

Step-by-step explanation:

Let points D, E and F have coordinates $(x_D,y_D),\ (x_E,y_E)$ and $(x_F,y_F).$

1. Midpoint M of segment DF has coordinates

$\left(\dfrac{x_D+x_F}{2},\dfrac{y_D+y_F}{2}\right).$

2. Midpoint N of segment EF has coordinates

$\left(\dfrac{x_E+x_F}{2},\dfrac{y_E+y_F}{2}\right).$

3. By the triangle midline theorem, midline MN is parallel to the side DE of the triangle DEF, then points M and N are endpoints of the midsegment for DEF that is parallel to DE.

6 0

3 years ago