Https://www.khanacademy.org/math/cc-sixth-grade-math/cc-6th-data-statistics/cc-6th/v/calculating-interquartile-range-iqr
This is a link that I gave to my little sister that helped her understand what interquartile range is. It has an example as well! I hope this helps!
Answer:
The answer is below
Step-by-step explanation:
Two polygons are said to be congruent if they have the same size and shape that is their corresponding angles and sides are equal.
Hence since Quadrilaterals ABCD is congruent to EFGH, then their corresponding angles and sides are equal.
In quadrilateral ABCD:
∠A + ∠B + ∠C + ∠D = 360° (sum of angles in a quadrilateral)
Substituting:
47 + 39 + 112 + ∠D = 360
∠D + 198 = 360
∠D = 360 - 198
∠D = 162°
The image of Quadrilaterals ABCD and EFGH is not given but let us assume that they have the same orientation, hence:
∠A = ∠E = 47°
∠B = ∠F = 39°
∠C = ∠G = 112°
∠D = ∠H = 162°
Your answer is 250 yards you basically just subtract the numbers it gives you from the 294....
Answer:The answer is Equal.
Step-by-step explanation:First you need to add A and 2A together. that equals 3a. Since 3 is left , it could be -1 and 4 because it would equal the same thing hope this helped :)
Answer:
Step-by-step explanation:
Simply plug in 10 for <em>n</em>
9(1/3)¹⁰⁻¹
9(1/3)⁹
9(1/19683)
9/19683
