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denpristay [2]
3 years ago
14

Please answer the following in the image below :)

Mathematics
2 answers:
madam [21]3 years ago
7 0

Answer:

srry it does not show me the image

Step-by-step explanation:

Delicious77 [7]3 years ago
4 0
The first answer is 1.09 the second answer is 1.11 the third answer is 1.12 the last answer is 1.08
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What is the are of a hexagon with a radius of 5 inches?
xxTIMURxx [149]
The area of a hexagon with a radius of 5 inches is 86.603. 
6 0
3 years ago
I need help with help on the one with the pink circle
podryga [215]

Answer:

15°

Step-by-step explanation:

The line in the middle of the triangle divides it into two triangles.  These two triangles are equal.  You can see this because the given angle (90°) is equal for both sides, and the bottom sides (23) are also equal to each other.  

Since the triangles are equal, this means that the given angle of 75° also applies to the other side.  The total degrees a triangle can have is 180°.  Use the given angles to solve for the unknown angle.

75° + 90° + x = 180°

165° + x = 180°

x = 15°

The angle measure will be 15°.

4 0
4 years ago
This is how you solve this problem: 4/5 = 3 = 4/5 x 3<br> True<br> False
ivann1987 [24]

Answer:

false

Step-by-step explanation:

because when solving fraction as a equation you divide

6 0
3 years ago
The length of a rectangular prism is 8
Lena [83]
Surface area is:

W=width
L=length
H=height

S=2*(L*W+L*H+W*H)

replacing the values

250=2*(8*W+8*1+W*1)

250=2*(8*W+8+W)

250=2*(9*W+8)

dived each member by 2

125=9W+8

9W=125-8

9W=117

\boxed{\boxed{W=13~unit~of~measure}}

The volume of a rectangular prism is

V=L*H*W

V=8*1*13

\boxed{\boxed{V=104~unit~of~volume}}
3 0
4 years ago
If a pool is 4 m wide and 16 m diagonally across, how long is the pool? (Pyth. Theorem)
alukav5142 [94]

Answer:

L=4\sqrt{15}\ m

or

L=15.49\ m

Step-by-step explanation:

we know that

Applying the Pythagorean Theorem in the rectangular pool

d^2=L^2+W^2

where

d is the diagonal of the pool

L is the length of the pool

W is the wide of the pool

we have

d=16\ m\\W=4\ m

substitute the given values

16^2=L^2+4^2

solve for L

L^2=16^2-4^2\\L^2=240\\L=\sqrt{240}\ m

simplify

L=4\sqrt{15}\ m

or

L=15.49\ m

4 0
3 years ago
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