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Nimfa-mama [501]
3 years ago
15

Help with this please

Mathematics
1 answer:
saul85 [17]3 years ago
8 0
7/8 because you subtract them both by either turning them into decimals and subtracting and the
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Help idk how to do this ASAP please
Sergio039 [100]

Answer:

The area of ∆DEF = 4.5in²

Step-by-step explanation:

From the above diagram,

∆BAC ~∆DEF

It is important to note that if two triangles are similar, the ratio of their areas is equal or equivalent to the ratio of the areas of their sides

This means for the above question, that

We have the bigger triangle = ∆BAC has a side of 4 in and Area = 8 in²

The small triangle has a side of 3in

Finding the scale factor k = ratio of the sides of both Triangles

k = 4/3

k² = (4/3)²

k² = 16/9

Hence,

Area of ∆BAC/ Area of ∆DEF = 16/9

8in²/Area of ∆DEF = 16/9

We cross Multiply

8 in² × 9 = Area of ∆DEF × 16

Divide both sides by 16

Area of ∆DEF = 72/16

= 4.5in²

Therefore, the Area of ∆DEF rounded to the nearest tenth = 4.5in²

8 0
3 years ago
How is the 4 in 864 related to the 4 in 846
hichkok12 [17]
The 4 in 846 is 10 times more than the 4 in 864
8 0
3 years ago
Read 2 more answers
What is the LCD of 1/2 and 3/5
bagirrra123 [75]

Answer:

10

Step-by-step explanation:

How you find LCD (lowest common denominator) is that you have to look at the denominator (the bottom number) and try to find the lowest multiple between both of the numbers that is on the bottom (in this case it is 2 and 5). Sometimes you have to multiply both denominators together to get a LCD.

Example of multiplying two denominators together to get an LCD:

1/3 and 1/13 LCD is 39 because you multiply 3 and 13.

1/5 and 1/4 LCD is 20 because you multiply 5 and 4.

8 0
3 years ago
Find BC<br> (triangle)<br> sides = 20mi, 22mi<br> inside = 95 degrees
Hunter-Best [27]
To solve this problem you need to know the law of cosines.

7 0
4 years ago
Trigonometry: <br>1) Work out the bearing from B to C. <br>2) Calculate the bearing of D from B
kakasveta [241]

Answer:

see below

Step-by-step explanation:

a bearing is the angle in degrees measured clockwise from north.

Triangle ABC is a right triangle

Tan C = opp side / hyp

tan C = AB / CA

tan C = 30/30

tan C = 1

taking the inverse tan

tan ^ -1 tan C = tan ^ -1 ( 1)

C = 45 degrees

This is 90+45 degrees from North

135 degrees from north

Tan B = opp side / hyp

tan B = AD/BA

tan B = 45/30

tan B = 3/2

taking the inverse tan

tan ^ -1 tan B = tan ^ -1 ( 3/2)

D = 56.30993247

Add 180 degrees

180+56.30993247

236.3099325 from north

7 0
4 years ago
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