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3 years ago

7

Help please! I can’t seem to solve this!!!

2 answers:

tiny-mole [99]3 years ago

8 0

Answer: C

Step-by-step explanation:

exis [7]3 years ago

8 0

Answer:

C

Step-by-step explanation:

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It take 23 mins for the drive

He needs to reach the airport by a quarter before 6

a quarter before 6 = 5.45
So he needs to leave 23 mins before 5.45

23 mins before 5.45 = 5.22

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3 years ago

HELP ASAP question 5!!!

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Step-by-step explanation:

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3 years ago

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Step-by-step explanation:

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3 years ago

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madreJ [45]

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3 years ago

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Organizers of an outdoor concert will use 320 feet of fencing to fence off a rectangular vip section. What is the maximum area t

solong [7]

<u>Answer-</u>

<em>The maximum area that they can fence off is</em><em> 6400 ft²</em>

<u>Solution-</u>

Organizers of an outdoor concert will use 320 feet of fencing to fence off a rectangular vip section.

i.e the perimeter of the rectangular section is 320 feet

Let us assume,

x = length of the rectangular section

y = breadth of the rectangular section

Hence,

$\Rightarrow 2(x+y)=320\\\\\Rightarrow x+y=160\\\\\Rightarrow y=160-x$

Now, we have to find the maximum area for which they can fence that off.

The area of the rectangular section is,

$=x\cdot y$

So we have to maximize the area function.

$\Rightarrow f(x)=x\cdot y$

Putting the value of y,

$\Rightarrow f(x)=x\cdot (160-x)=160x-x^2$

$\Rightarrow f'(x)=160-2x$

$\Rightarrow f''(x)=-2$

Finding the critical values,

$\Rightarrow f'(x)=0$

$\Rightarrow 160-2x=0$

$\Rightarrow 2x=160$

$\Rightarrow x=80$

∵ f"(x) is negative (i.e -2), so for the value of x=80, f(x) or area function will be maximum.

$f(x)_{\text{at x=80}}=f(80)=160(80)-(80)^2=12800-6400=6400$

Therefore, the maximum area that they can fence off is 6400 ft²

8 0

3 years ago