Mass of MnO2 = 25 g
The reaction would be 3MnO2 + 4Al --> 3Mn(s) + 2Al2O3
Molar mass of Al = 26.982 g/mol
Molar mass of MnO2 = 54.938 + 2(15.999) = 86.936 g/mol
Calculating the moles = 25 / 86.936 = 0.2876 mol.
Mole ratio MnO2 and Al considering the equation = 3 mol of MnO : 4 mol of Al
Calculating the moles of Al = 0.2876 mol MnO2 x (4 mol of Al / 3 mol of MnO)
Number of moles of Al = 0.3834
Getting the mass in grams as asked = 0.3834 mol x 26.982 g/mol = 10.34 grams.
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The coefficient of Fe would be 2, the coefficient of Cl2 would be 3, while the coefficient of FeCl2 would be 2.
The balanced equation of the reaction would be as follows:

Thus, the coefficients of Fe, Cl2, and FeCl3 respectively would be 2, 3, and 2.
In other words, 2 moles of Fe require 3 moles of Cl2 to produce 2 moles of FeCl3 in a complete reaction.
More on balancing chemical equations can be found here: brainly.com/question/8062886?referrer=searchResults
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