If you use disposable water bottles, here are some important concerns you should know about how they’re made as well as the problems they cause for the planet, your health, and your wallet.

3 0

3 years ago

A sample of iron metal is placed in a graduated cylinder. it is noted that 10.4 ml of water is displaced by the iron. the iron i

Pavel [41]

<h3>Answer:</h3>

162.43 g of FeCl₂

<h3>Explanation:</h3>

Step 1: Calculate mass of Fe;

As,

Density = Mass ÷ Volume

Or,

Mass = Density × Volume

Where Volume is the volume of water displaced = 10.4 mL

Putting values,

Mass = 7.86 g.mL⁻¹ × 10.4 mL

Mass = 81.744 g of Fe

Step 2: Calculate amount of FeCl₂;

The balance chemical equation is as follow,

Fe + 2 HCl → FeCl₂ + H₂ ↑

According to this equation,

55.85 g (1 mol) Fe produced = 110.98 g (1 mol) of FeCl₂

So,

81.744 g Fe will produce = X g of FeCl₂

Solving for X,

X = (81.744 g × 110.98 g) ÷ 55.85 g

X = 162.43 g of FeCl₂

7 0

3 years ago

A reaction that absorbs energy

coldgirl [10]

Answer:

Endothermic Reaction

Explanation:

5 0

3 years ago

Read 2 more answers

The equilibrium constant for the reaction is 1.1 x 106 M. HONO(aq) + CN-(aq) ⇋ HCN(aq) + ONO-(aq) This value indicates that

kakasveta [241]

The given question is incomplete. The complete question is given here :

The equilibrium constant for the reaction is $1.1\times 10^6$ M.

$HONO(aq)+CN^- (aq)\rightleftharpoons HCN(aq)+ONO^-(aq)$

This value indicates that

A. $CN^-$ is a stronger base than $ONO^-$

B. HCN is a stronger acid than HONO

C. The conjugate base of HONO is $ONO^-$

D. The conjugate acid of CN- is HCN

Answer: A. $CN^-$ is a stronger base than $ONO^-$

Explanation:

Equilibrium constant is the ratio of product of the concentration of products to the product of concentration of reactants.

When $K_{p}>1$ ; the reaction is product favoured.

When $K_{p};$ ; the reaction is reactant favored.

$When K_{p}=1$ ; the reaction is in equilibrium.

As, $K_p>>1$ , the reaction will be product favoured and as it is a acid base reaction where $HONO$ acts as acid by donating $H^+$ ions and $CN^-$ acts as base by accepting $H^+$

Thus $HONO$ is a strong acid thus $ONO^-$ will be a weak conjugate base and $CN^-$ is a strong base which has weak $HCN$ conjugate acid.

Thus the high value of K indicates that $CN^-$ is a stronger base than $ONO^-$

7 0

3 years ago