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8090 [49]
3 years ago
9

Is there are a total of 7.3 x 10^29 atoms in a sample of glucose, C6H12O6(s),what amount in miles of glucose is in the sample?

Chemistry
1 answer:
Vadim26 [7]3 years ago
4 0

(7.3 x 10^29 atoms) / (24 atoms/molecule) / (6.022 x 10^23 molecules/mol) =  

5.1 x 10^4 mol C6H12O6

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A 1.00 L volume of HCl reacted completely with 2.00 L of 1.50 M Ca(OH)2 according to the balanced chemical equation below. 2HCl
Zigmanuir [339]
The first step is to find the number of moles of OH⁻ that reacted with the HCl.  To do this multiply 2.00L by 1.50M to get 3 moles of Ca(OH)₂.  Then you multiply 3 by 2 (there are 2 moles of OH⁻ per every 1 mole of Ca(OH)₂) to get 6 moles of OH⁻.  That means that you needed 6 moles of HCl since 1 mole of HCl contains 1 mole of H⁺ and equal amounts H⁺ and OH⁻ reacted with each other.  To find the molarity of the HCl solution you need to divide 6mol by 1L to get 6M.  Tat means that the concentration of the acid was 6M.

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Read 2 more answers
How many milliliters of 2.19 M H2SO4 are required to react with 4.75 g of solid containing 21.6 wt% Ba(NO3)2 if the reaction is
Setler [38]

Answer:

1.7927 mL

Explanation:

The mass of solid taken = 4.75 g

This solid contains 21.6 wt% Ba(NO_3)_2, thus,

Mass of Ba(NO_3)_2 = \frac {21.6}{100}\times 4.75\ g = 1.026 g

Molar mass of Ba(NO_3)_2 = 261.337 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{1.026\ g}{261.337\ g/mol}

Moles= 0.003926\ mol

Considering the reaction as:

Ba(NO_3)_2+H_2SO_4\rightarrow BaSO_4+2HNO_3

1 moles of Ba(NO_3)_2 react with 1 mole of H_2SO_4

Thus,

0.003926 mole of Ba(NO_3)_2 react with 0.003926 mole of H_2SO_4

Moles of H_2SO_4 = 0.003926 mole

Also, considering:

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Molarity = 2.19 M

So,

2.19=\frac{0.003926}{Volume\ of\ the\ solution(L)}

Volume = 0.0017927 L

Also, 1 L = 1000 mL

<u>So, volume = 1.7927 mL</u>

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