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3 years ago

Carlotta got to toy museum at 10:19 circle the letter of the correct answer

Mathematics

1 answer:

Elina [12.6K]3 years ago

4 0

Answer:

10:00 first one easy

Step-by-step explanation:

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Draw a histogram for the intervals 16-18, 19-21, 22-24, and 25-27 using the following data: 26, 16, 22, 27, 20, 24, 21, 27, 22,

wolverine [178]

Answer:

Step-by-step explanation:

Class Interval Variate Frequency

16-18 16 1

19-21 0 0

22-24 0 0

25-27 26,27 2

6 0

3 years ago

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-7(a - 3) = 11 - 7a<br> what’s the answer

natali 33 [55]

Answer:

the statement is false there is no solution

Step-by-step explanation:

step 1 -7(a-3)=11-7a

step 2 -7a+21=11-7a

step 3 cancel out the -7a's

step 4 you are left with 21=11 which does not work so it is false

8 0

3 years ago

What values of a and b make the equation true? StartRoot 648 EndRoot = StartRoot 2 Superscript a Baseline times 3 Superscript b

kramer

Option C: $a=3, b=4$ is the value of a and b

Explanation:

Given that the expression $\sqrt{648}=\sqrt{2^a\times3^b}$

We need to determine the value of a and b

Let us consider the term $\sqrt{648}$ and take the prime factorization of the term 648

Thus, we have,

648 divides by 2,

$648=2 \cdot 324$

324 divides by 2,

$648=2 \cdot 2 \cdot 162$

162 divides by 2,

$648=2 \cdot 2 \cdot 2 \cdot 81$

81 divides by 3,

$648=2 \cdot 2 \cdot 2 \cdot 3 \cdot 27$

27 divides by 3,

$648=2 \cdot 2 \cdot 2 \cdot 3 \cdot 3 \cdot 9$

9 divides by 3,

$648=2 \cdot 2 \cdot 2 \cdot 3 \cdot 3 \cdot 3 \cdot 3$

Thus, we have,

$\sqrt{648}=\sqrt{2^{3} \cdot 3^{4}}$

Therefore, equating the powers of 2 and 3, we get,

$a=3, b=4$

Hence, the value of a and b is 3 and 4

Thus, Option C is the correct answer.

4 0

3 years ago

Read 2 more answers

For fun question

ZanzabumX [31]

Consider the function $f(x)=x^{1/3}$ , which has derivative $f'(x)=\dfrac13x^{-2/3}$ .

The linear approximation of $f(x)$ for some value $x$ within a neighborhood of $x=c$ is given by

$f(x)\approx f'(c)(x-c)+f(c)$

Let $c=64$ . Then $(63.97)^{1/3}$ can be estimated to be

$f(63.97)\approxf'(64)(63.97-64)+f(64)$
$\sqrt[3]{63.97}\approx4-\dfrac{0.03}{48}=3.999375$

Since $f'(x)>0$ for $x>0$ , it follows that $f(x)$ must be strictly increasing over that part of its domain, which means the linear approximation lies strictly above the function $f(x)$ . This means the estimated value is an overestimation.

Indeed, the actual value is closer to the number 3.999374902...

4 0

3 years ago

6.8 * 10(2)<br> *keep in note that "2" is an exponent in this question*

Virty [35]

Answer:

Step-by-step explanation:

6.8 × $10^2$

= 68

5 0

3 years ago

Carlotta got to toy museum at 10:19 circle the letter of the correct answer​

Carlotta got to toy museum at 10:19 circle the letter of the correct answer