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irina1246 [14]
3 years ago
8

2y+2y+4y^3+4-3y^3+4+y​

Mathematics
2 answers:
Anastaziya [24]3 years ago
6 0
Y^3 + 5y +8 is the answer
RUDIKE [14]3 years ago
4 0

Answer:

y^3 + 5y + 8

Step-by-step explanation:

Collect like terms

4y^3 - 3y^3 + 2y + 2y + y + 4 + 4

= 1y^3 + 5y + 8 OR y^3 + 5y + 8

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A cashier has a total of 30 bills consisting of ones, fives and twenties. the number of twenties is 5 less than the number of on
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Let us say that:

a = ones

b = fives

c = twenties

 

So that the total money is:

1 * a + 5 * b + 20 * c = 229

=> a + 5b + 20c = 229                                       --> eqtn 1

 

We are also given that:

c = a – 5                                                                --> eqtn 2

a + b + c = 30                                                      --> eqtn 3

 

Rewriting eqtn 3 in terms of b:

b = 30 – a – c

Plugging in eqtn 2 into this:

b = 30 – a – (a – 5)

b = 35 – 2a                                                           --> eqtn 4

 

Plugging in eqtn 2 and 4 into eqtn 1:

a + 5(35 – 2a) + 20(a – 5) = 229

a + 175 – 10a + 20a – 100 = 229

11a = 154

a = 14

 

So,

b = 35 – 2a = 7

c = a – 5 = 9

 

Therefore there are 14 ones, 7 fives, and 9 twenties.

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