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irina1246 [14]
4 years ago
8

2y+2y+4y^3+4-3y^3+4+y​

Mathematics
2 answers:
Anastaziya [24]4 years ago
6 0
Y^3 + 5y +8 is the answer
RUDIKE [14]4 years ago
4 0

Answer:

y^3 + 5y + 8

Step-by-step explanation:

Collect like terms

4y^3 - 3y^3 + 2y + 2y + y + 4 + 4

= 1y^3 + 5y + 8 OR y^3 + 5y + 8

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I need help is it A B C or D
Aneli [31]
Its A.................

coz x*6=9*5
5 0
4 years ago
Rewrite 9 5/2 in radical form.
Alekssandra [29.7K]

Answer:

√9^5

Step-by-step explanation:

5 0
3 years ago
Let f(x) = -3x2 + 6x. Find f(2).
rusak2 [61]

Answer:

f(2) = 0

Step-by-step explanation:

All we have to do is substitute 2 in for x everywhere in the expression defined by f(x)

-3(2)(2) + 6(2)

-12 + 12

0

8 0
3 years ago
Gabriel wants to paint the model. How
enyata [817]

Answer:

<h2>The area of the base is 144 square inches.</h2><h2>The area of each triangular face is 66 square inches.</h2><h2>Grabiel needs 408 square inches of paint.</h2>

Step-by-step explanation:

The complete problem is attached.

Notice that the figure is a square pyramid, where its base dimensions are 12 inches by 12 inches, which represents an area of

B=12 \times 12 = 144 \ in^{2}

The slant height of the pyramid is 11 inches, which allow us to find the area of each triangle face

A=\frac{1}{2}bh =\frac{1}{2}(12)(11)= 66 \ in^{2}

But there are four triangle faces, so A_{faces} =4(66)=264 \ in^{2}.

Therefore, the area of each triangular face is 66 square inches.

So, the total surface area would be the sum

S=144+264=408 \ in^{2}

Therefore, Gabriel needs 408 square inches to paint the whole model.

4 0
4 years ago
charlotte is playing a beanbag toss game. she has a 10% chance of hitting the 3- point hole, a 30% chance of hitting the 1- poin
34kurt

Answer:

20

Step-by-step explanation:

The expected value of a toss is:

E(X) = (0.10) (3) + (0.30) (1) + (0.60) (0)

E(X) = 0.6

If she scores an average of 0.6 points per toss, then the expected number of tosses needed to get 12 points is:

12 / 0.6 = 20

Using a random number table, we can assign digit 0 as a 3-point hole, digits 1-3 as a 1-point hole, and digits 4-9 as no points.  Read the digits and add the points until you get 12 points.  The number of digits read is the number of beanbag tosses.

5 0
3 years ago
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