If two individual are heterozygous for both traits then there genotype will each look like this PpLl. To find the probability, you need to do a cross with both traits. Each parent has the possibility of giving the following combinations: PL, Pl, pL, pl.
PL Pl pL pl
PL PPLL PPLl PpLL PpLl
Pl PPLl PPll PpLl Ppll
pL PpLL PpLl ppLL ppLl
pl PpLl Ppll ppLl ppll
Polka dot tail/ long lashes: 9/16
Polka dot tail/ short lashes: 3/16
Solid Tail / long lashes: 3/16
solid tail/ short lashes 1/16
The answer is (C) 9:3:3:1 ratio with 9 polka dot tails and long eyelashes, 3 polka dot tails and short eyelashes, 3 solid tails and long eyelashes (there seems to be a typo in the question) and 1 short tail short eyelash
Plants, algae, and fungi. I'm not sure about the fungi part
Answer:
the ocean helps slow the effects of gobal warming by absorbing the excess heat - trapping CO2 from the atmosphere.
Hope it helps!
5-fold 10-fold 2-fold 2.5-fold IgG has the same avidity as the IgM.compared to the igg assuming that both the isotopes have the same affinity
The Isotopes are the members of the family of an element that all have the same number of the protons but the different numbers of the neutrons. The number of the protons in the nucleus that determines the element's of atomic number on the Periodic Table. For example, carbon has the six protons and is atomic number 6.
Radioactive are isotopes have many useful applications. In the medicine, for example, cobalt-60 is the extensively employed as the radiation source to arrest the development of the cancer. Other radioactive isotopes are also used as tracers for the diagnostic purposes as well as in the research on the metabolic processes.
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The answer is 0.43
To calculate p we will use one of two formulas of the <span>Hardy-Weinberg principle:
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p² + 2pq + q² = 1 and p + q = 1
where:
p - the frequency of the allele for long legs which is a dominant trait.
q - the frequency of the allele for short legs which is a recessive trait.
p² - the frequency of dominant homozygote (with long legs)
2pq - the frequency of heterozygote (with long legs)
q² - the frequency of recessive homozygote (with short legs)
So, 33 of 100 organisms have short legs. The frequency of recessive homozygote is represented by q²:
q² = 33/100 = 0.33
⇒ q = √0.33 = 0.57
Using the formula:
p + q = 1
p = 1 - q = 1 - 0.57 = 0.43
Therefore, p = 0.43