If the length of JK is 16.4 miles, it will be diameter of this circle, the radius will be JK/2 = 8.2 miles
As we know the length of circle is 2π*r in this case r = 8.2
The arc JM is 1/4 length of the whole circle so arc JM = (2π*8.2)*(1/4) = 2π*8.2/4 = π*8.2/2 = π*4.1
if we assume that π=3.14 the answer will be 3.14 * 4.1 = 12.874.... And as the answer needs to be rounded to the nearest tenth it will be 12.874≈12.9
So the answer will be 12.9
78.5= (3.14)r^2
25=r^2
5=r
So, the radius of a circle with an area is 78.5 cm^2 is 5 cm^2
Answer:
umm i'm not rly sure what's going on here...but here's how i'd do it
Step-by-step explanation:
3280.84x12=39370.08 which is about 3,9370 feet.
to double check let's do an algebraic expression
1/3280.84=x/12 cross multiply
x(1)=3280.84(12) simplify
x=39370.08
hope that helped.
Answer:
D. unfavorable fixed overhead flexible minus budget variance
Step-by-step explanation:
As the cost of the equipment is increasing the fixed efficiency and idle capacity variance would be unfavorable resulting in an unfavorable fixed overhead flexible minus budget variance.
The expenses of the machinery are the fixed indirect costs which result in fixed overhead variances. Since it is related to the working of the machinery it would result in efficiency and idle capacity variances that in turn would give unfavorable fixed overhead of the flexible minus budget variance.
6h + 5h - 3j = 11h - 3j (all u can do is combine like terms...if they're not like terms, they cannot be combined)
