Answer:
minimum of 13 chairs must be sold to reach a target of $6500
and a max of 20 chairs can be solved.
Step-by-step explanation:
Given that:
Price of chair = $150
Price of table = $400
Let the number of chairs be denoted by c and tables by t,
According to given condition:
t + c = 30 ----------- eq1
t(150) + c(400) = 6500 ------ eq2
Given that:
10 tables were sold so:
t = 10
Putting in eq1
c = 20 (max)
As the minimum target is $6500 so from eq2
10(150) + 400c = 6500
400c = 6500 - 1500
400c = 5000
c = 5000/400
c = 12.5
by rounding off
c = 13
So a minimum of 13 chairs must be sold to reach a target of $6500
i hope it will help you!
Answer:
C
Step-by-step explanation:
A function is where each input has a single output.
(A) There can be a different amount of students in a class (e.g. 21 or 22) that have the same class length
(B) There can be multiple things that Mike can order with $1
(D) There can be multiple students have the same GPA
(C) There is one button for each snack item
25 * 5 + 15 * 3 - 40 * 2 =
125 + 45 - 80 =
170 - 80 =
90
