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agasfer [191]
3 years ago
5

Jayden rotates a trapezoid around its vertical axis of symmetry to make a solid figure. What is the shape of a vertical cross se

ction of the solid figure?
A)square
B)triangle
C)rectangle
D)trapezoid
Mathematics
1 answer:
nirvana33 [79]3 years ago
8 0
<span>Jayden rotates a trapezoid around its vertical axis of symmetry to make a solid figure. The shape of a vertical cross section of the solid figure is D. a trapezoid.
The vertical cross section of the solid figure is the same as the figure itself, at least in this case.
</span>
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PLS HELP ITS MY FINAL EXAM What is the area of the base of the cone below? A cone with height 12 feet and volume 90 feet cubed.
hoa [83]

Answer:

A=22.5\ \text{feet}^2

Step-by-step explanation:

We have,

Height of a cone is 12 feet

Volume of the cone is 90 feet

It is required to find the area of the base of the cone.

The base of a cone is circular in shape.

The formula used to find the volume of a cone is given by :

V=\dfrac{1}{3}\pi r^2 h

here, \pi r^2=A (area of base of cone)

V=\dfrac{1}{3}\times Ah\\\\A=\dfrac{3V}{h}\\\\A=\dfrac{3\times 90}{12}\\\\A=22.5\ \text{feet}^2

So, the area of the base of the cone is 22.5\ \text{feet}^2.

3 0
3 years ago
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Wittaler [7]

Answer:3

Step-by-step explanation:

A. 2^4(4n) = 2^48

2^16n = 2^48

16n = 48

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5 0
3 years ago
Make a table of ordered pairs for the equation.   y= 1 2 x−3<br><br> PLEASE HELP !!
Hunter-Best [27]
All you need to do is plug in some x values and find the correspoding y value
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3 years ago
Question 4 (1 point)
Nostrana [21]

Answer:

The ball will hit the ground at 10 seconds and its maximum height is 1024 feet.

Step-by-step explanation:

Height of a mountain, h = 90 feet

Upward velocity of a ball, u = 64 ft/s

Its height as a function of time can be written by using the second equation of motion as follows :

f(x) = -16t^2 + 64t + 960 .....(1)

When it will hit the ground, f(x) = 0

-16t^2 + 64t + 960=0\\\\16(-t^2+4t+60)=0\\\\-t^2+4t+60=0

It is quadratic equation.

t = -6 s and t = 10 s

Neglecting -6 seconds, the ball will hit the ground at 10 seconds.

For maximum height,

Put f'(x) = 0

-32t+64=0\\\\\\t=\dfrac{64}{32}\\\\t=2\ s

Put t = 2 in equation (1)

f(2) = -16(2)^2 + 64(2) + 960\\\\=1024\ \text{feet}

Hence, the ball will hit the ground at 10 seconds and its maximum height is 1024 feet.

5 0
2 years ago
. Write an equation for the line parallel to y = 7x + 11 that contains P(-5, 7).
m_a_m_a [10]
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x – 7 = -42y + -35

x – 7 + 35 = -42y

x + 28 = -42y

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c) y – 7 = 7(x + 5)

y – 7 = 7x + 35

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b) y – 7 = -7(x + 5)

y – 7 = -7x -35

y = -7x – 28

d) y + 7 = 7(x + 5)

y + 7 = 7x + 35

y = 7x + 28
3 0
2 years ago
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