So in order for us to know the area of the square that is not covered by the circle, we need to find first both the areas of the square and the circle.
So for the area of the square it is A = sxs. And for the circle is A = pi*r^2.
Let us find the area of the square first given that the side is 3 inches.
So A = 3*3
A = 9 square inches.
Next is the area of the circle. Since the center of the circle is the same with the center of the square, the radius would be 1.5.
SO, A = (3.14)(1.5)^2
A = 2.25 (3.14)
A = 7.065 square inches.
Next, we deduct the area of circle from area of square and the result would be 1.935 <span>in². So the answer for this would be option B.
Hope this answer helps.</span>
We want to find the coeficient of the y terms when added together so find all the y terms
+12y and +2y
we add them together
12y+2y=(12+2)y=(14)y=14y
coeficient is 14
the constant is the number that is set already or the number that doesn't have it multiplied by a placeholder exg. 4 is a constnat but 4x is not so find the constants
+5 and +8
we add
5+8=13
the constant is 13
y coeficient=14
constant=14
Answer:
4y^6
Step-by-step explanation:
Take out the constants:
40y^14/10y^8
= 40/10 * y^14 / y^8
= 4 * y^(14-8)
= 4 * y^6
= 4y^6
Hope this helped you :3
Answer:
1
-12
3
6
Step-by-step explanation:
