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adell [148]
1 year ago
14

2(x + 2) + 2 = 2(x + 3) + 1

Mathematics
1 answer:
Maslowich1 year ago
6 0

Answer:

No solution

Step-by-step explanation:

5(x + 4) – x = 4(x + 5) – 1

x = ?

Solution:

5(x+4)−x=4(x+5)−1

Apply Distributive property:

  • (5)(x)+(5)(4)−x=(4)(x)+(4)(5)−1
  • 5x+20−x=4x+20−1

Combine Like Terms:

  • (5x−x)+(20)=(4x)+(20−1)
  • 4x+20=4x+19
  • 4x+20=4x+19

Subtract 4x from both sides:

  • 4x+20−4x=4x+19−4x
  • 20=19

Subtract 20 from both sides:

  • 20−20=19−20
  • 0=−1

There isn't any solutions.

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Read 2 more answers
(x^(2)-11x+30)/(x^(2)-25)*(x^(2)+6x+5)/(x-5x-6) simplify the rational expression
DanielleElmas [232]
Simplify the following:
((x^2 - 11 x + 30) (x^2 + 6 x + 5))/((x^2 - 25) (x - 5 x - 6))

The factors of 5 that sum to 6 are 5 and 1. So, x^2 + 6 x + 5 = (x + 5) (x + 1):
((x + 5) (x + 1) (x^2 - 11 x + 30))/((x^2 - 25) (x - 5 x - 6))

The factors of 30 that sum to -11 are -5 and -6. So, x^2 - 11 x + 30 = (x - 5) (x - 6):
((x - 5) (x - 6) (x + 5) (x + 1))/((x^2 - 25) (x - 5 x - 6))

x - 5 x = -4 x:
((x - 5) (x - 6) (x + 5) (x + 1))/((x^2 - 25) (-4 x - 6))

Factor -2 out of -4 x - 6:
((x - 5) (x - 6) (x + 5) (x + 1))/(-2 (2 x + 3) (x^2 - 25))

x^2 - 25 = x^2 - 5^2:
((x - 5) (x - 6) (x + 5) (x + 1))/(-2 (x^2 - 5^2) (2 x + 3))

Factor the difference of two squares. x^2 - 5^2 = (x - 5) (x + 5):
((x - 5) (x - 6) (x + 5) (x + 1))/(-2(x - 5) (x + 5) (2 x + 3))

((x - 5) (x - 6) (x + 5) (x + 1))/((x - 5) (x + 5) (-2) (2 x + 3)) = ((x - 5) (x + 5))/((x - 5) (x + 5))×((x - 6) (x + 1))/(-2 (2 x + 3)) = ((x - 6) (x + 1))/(-2 (2 x + 3)):
((x - 6) (x + 1))/(-2 (2 x + 3))

Multiply numerator and denominator of ((x - 6) (x + 1))/(-2 (2 x + 3)) by -1:

Answer: (-(x - 6) (x + 1))/(2 (2 x + 3))
4 0
3 years ago
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