Question

Find the vertex of the parabola given by y=2x^2-4x-1

Answer 1

Given the quadratic y = 2x^2-4x-1,  I identify A = 2, B= -4 and C = -1. The axis of symmety: x = -b/2a  --> 4/2(2) = 4/4 = 1. Therefore, the x-coordinate of the vertex is 1. To find the y-coordinate, I plug in 1 for x into the quadratic. Hence, y = 2(1)^2-4(1)-1 ---> -3.  The coordinates of the vertex are (1,-3).