3 years ago

Find the vertex of the parabola given by y=2x^2-4x-1

1 answer:

3 0

Given the quadratic y = 2x^2-4x-1, I identify A = 2, B= -4 and C = -1. The axis of symmety: x = -b/2a --> 4/2(2) = 4/4 = 1. Therefore, the x-coordinate of the vertex is 1. To find the y-coordinate, I plug in 1 for x into the quadratic. Hence, y = 2(1)^2-4(1)-1 ---> -3. The coordinates of the vertex are (1,-3).

You might be interested in

The tent shown has fabric covering all four sides and the floor. What is the minimum amount of fabric needed to construct the te

Vesna [10]

Answer:

The answer is "152 ft"

Step-by-step explanation:

Please find the attached file.

The area of the square $(8 \times 5=40)$ can be found on the foot.