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Triss [41]
2 years ago
12

Find the value of Y .....

Mathematics
1 answer:
vekshin12 years ago
4 0

Answer:

y = 6 \sqrt{3}  \: units

Step-by-step explanation:

In order to find the value of y, first we need to find the length of the perpendicular dropped from one of the vertices of the triangle to its opposite side.

By geometric mean theorem:

Length of the perpendicular

=\sqrt{9\times 3}

=\sqrt{27}\: units

Next, by Pythagoras theorem:

{y}^{2}  =  {9}^{2}  +  {( \sqrt{27} )}^{2}  \\  \\  {y}^{2}  = 81 + 27 \\  \\  {y}^{2}  = 108 \\  \\ y =  \sqrt{108}  \\  \\ y =  \sqrt{36 \times 3}  \\  \\ y =  \sqrt{ {6}^{2}  \times 3}  \\  \\ y = 6 \sqrt{3}  \: units

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