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Margaret [11]
3 years ago
8

Solve the inequality. X-5 < 16 A. X> 21 B. x<21 C. x< 11 D. x> 11

Mathematics
2 answers:
tiny-mole [99]3 years ago
8 0

Answer:

B. x < 21

Step-by-step explanation:

x - 5 < 16

  +5    +5

x      <  21

The answer would be B.

larisa [96]3 years ago
4 0

Answer:

x < 21

Step-by-step explanation:

x - 5 < 16

x < 21           Add 5 to both sides

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Diseases tend to spread according to the exponential growth model. In the early days of AIDS, the growth factor (i.e. common rat
weqwewe [10]

Answer:

1,887,436,800

Step-by-step explanation:

f(t) = a·b^t

f (t) = number of cases at year t

a = starting value = 1800 in 1983

b = growth factor = 2

t = years since 1983 = 2003 - 1983 = 20

f(t) = 1800·(2)^20 =

1,887,436,800

wyzant

philip p

5 0
2 years ago
Allie has two cars- a truck and a sedan. Last week, she used 3 gallons of gas in the truck and 5 gallons of gas in the sedan and
gavmur [86]

Answer:

sedan = 26 miles/gallon

truck = 17 miles/gallon

Step-by-step explanation:

try to write the text in mathematical format as a system of equations

t=truck s=sedan

\left \{ {{3t+5s=181} \atop {7t+6s=275}} \right.

first equation can be written as

t= (181-5s)/3

we can use it in the second equation and rewrite it as

7[(181-5s)/3]+6s = 275

7(181/3 -5/3s) + 6s = 275

1267/3 - 35/3s + 6s = 275

-35/3s + 18/3s = 275-1267/3

-35/3s + 18/3s = 825/3 - 1267/3

-35s + 18s = 825 -1267

-17s = -442     s = 442/17 = 26 sedan has an average of 26 miles/gallon

we use this value of s in the first equation

3t + 5*26=181      3t=181-130   t= 51/3 = 17 truck has an average of 17 miles/gallon

5 0
3 years ago
What is 3.62 rounded to the nearest thousand
spayn [35]
It would round up to 3.620
:)
7 0
3 years ago
What is the value of t? t−122=3t2−3 –3 –1 1 3
enot [183]

If your equation is ...

t-122=3t^2-3

then it has no real solutions, and certainly no integer solutions.

_____

The attached graph show the left side is never equal to the right side of this equation for any real values of t.

4 0
3 years ago
Read 2 more answers
find the amount at compound interest that #600 would be at 3% the end of the first year, 2% at the end of the second year​
zaharov [31]

Step-by-step explanation:

First we find the interest at the end of the first year.

Principal = #600

Rate = 3%

Time = 1 year

Interest = \frac{600 * 3 * 1}{100}

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Amount = #618 at the end of the first year

Now at the end of the second year.

Principal now = #618

Rate now = 2%

Time = 1 year

Interest = \frac{618 * 2 * 1}{100}

             = #12.36

Amount = #630.36 at the end of the second year

4 0
3 years ago
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