Question

The position (resp. velocity, resp. acceleration) at time t of a particle of mass m is c(t) (resp. v(t), resp. a(t)). Let F(x, y, z) = (f(x, y, z), g(x, y, z), h(x, y, z)) be a C 1 mapping representing a force at (x, y, z). Then Newton’s second law states: F(c(t)) = ma(t).
Show that d dt[mc(t) × v(t)] = c(t) × F(c(t))

Answer 1

Answer:

(f(x, y, z), g(x, y, z), h(x, y, z))

Step-by-step explanation:

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