The position (resp. velocity, resp. acceleration) at time t of a particle of mass m is c(t) (resp. v(t), resp. a(t)). Let F(x, y
, z) = (f(x, y, z), g(x, y, z), h(x, y, z)) be a C 1 mapping representing a force at (x, y, z). Then Newton’s second law states: F(c(t)) = ma(t). Show that d dt[mc(t) × v(t)] = c(t) × F(c(t))
