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Goshia [24]
3 years ago
13

If you need help with math go to cymath hoped i helped :>

Mathematics
2 answers:
lidiya [134]3 years ago
6 0
Thankk you !!! i rlly needed it !!
kipiarov [429]3 years ago
5 0

Answer:

Can I get a brainliest- and also that so nice!!✨

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Find the area of the shaded region. Use 3.14 for pi. Round to the nearest tenth.<br> r = 15<br> 110
Svetradugi [14.3K]

Answer:

110/360=11/36 (I will get back to this)

The area of the circle would be 225 pi using the formula pi r^2. So you multiply 225pi by 11/36 to find the area.  This rounds to 215.98

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Which statement is true about the patterns in the two tables ?
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Answer: The fourth one

Step-by-step explanation:

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Solve 9= 1 + 8x - 8.
insens350 [35]
9 = 1 + 8x - 8

Add 8 to both sides:
17 = 1 + 8x

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artcher [175]
9 is the LCM, and the GCF is 27
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Solve the following problem. Write the complete proof in your paper homework and for online (only) complete the probing statemen
Charra [1.4K]

Answer:

OM = ON by using concurrency of Δs BOM and DON

Step-by-step explanation:

In the figure ABCD:

∵ AB // CD

∵ CB // AD

∵ In any quadrilateral If every two sides are parallel then

  it will be a parallelogram

∴ ABCD is a parallelogram

∴ AC and BD bisects each other at O ⇒ (properties of parallelogram)

∴ OD = OB ⇒ (1)

∵ BC // AD

∴ m∠CBD = m∠ADB ⇒ alternate angles

∵ M ∈ BC , N ∈ AD , O ∈ BD

∴ m∠MBO = m∠NDO ⇒ (2)

∵ BD intersects MN at O

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From (1) , (2) and (3)

∴ ΔBOM ≅ ΔDON

∴ OM = ON

3 0
3 years ago
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