The domain- Is the function provides an "output" or value for each member of the domain
Range- The difference between the lowest and highest values.
2.8 = 2 + 0.8
*let's analyze the decimal 0.8 as a fraction
0.8 = 8/10
*but if we divide the numerator and denominator by the same common factor of 2, we find that the fraction can be reduced to:
(8/2)/(10/2) = (4)/(5) = 4/5
*now evaluating the whole value of 2 (from the 2.8), we know there are a total of (5) - fifths in order to make a whole, so for 2 whole, we require:
2*(5/5) = (2*5)/5 = 10/5
*Now we add the fractions together:
2 = 10/5
0.8 = 4/5
10/5 + 4/5
*add numerators only, the denominator stays as a 5
(10 + 4)/5 = 14/5
*there are no common factors between 14 & 5 (other than 1, but that won't help reduce the fraction any), so the fraction is in it's simplest form:
answer is: 14/5
Answer:

Step By Step Explanation:
Area Of Rhombus: 
Identify 'p'
5 + 5 = 10
p = 10
Identify 'q'
10 + 10 = 20
q = 20


➤ 
A because -2 -3 -4 ext are less than -1
Answer:
<h3>B. 4units</h3>
Step-by-step explanation:
Find the diagram attached. The diagram is a similar triangle.
From the diagram, XZ/XY = CA/AB
Given XZ = 2x-2+2x-2 = 4x-4
XY =5x-7
CA = 2x-2
AB= x+1
On substituting this parameters into the formula to get x first
4x-4/5x-7 = 2x-2/x+1
cross multiply
(4x-4)(x+1) = 5x-7(2x-2)
open the parenthesis
4x²+4x-4x-4 = 10x²-10x-14x+14
4x²-4 = 10x²-24x+14
10x²-4x²-24x+14+4 = 0
6x²-24x+18 = 0
x²-4x+3 = 0
x²-3x-x+3 = 0
x(x-3)-1(x-3) =0
(x-3)(x-1) = 0
x = 3 and 1
Next is to get length AX.
Given AX = 2x-2
Substitute x = 3 into the expression
AX = 2(3)-2
AX = 6-2
AX = 4 units
Hence the measure of length AX is 4 units