Ok so m=2 and b=6
So we just have to put it into an equation.
y=2x+6
Answer:
it's going to be 3 and 6
Step-by-step explanation:
hope this one is right :)
We know that
case a)the equation of the vertical parabola write in vertex form is
y=a(x-h)²+k,
where (h, k) is the vertex.
Using our vertex, we have:
y=a(x-2)²-1
We know that the parabola goes through (5, 0),
so
we can use these coordinates to find the value of a:
0=a(5-2)²-1
0=a(3)²-1
0=9a-1
Add 1 to both sides:
0+1=9a-1+1
1=9a
Divide both sides by 9:
1/9 = 9a/9
1/9 = a
y=(1/9)(x-2)²-1
the answer isa=1/9case b)the equation of the horizontal parabola write in vertex form is
x=a(y-k)²+h,
where (h, k) is the vertex.
Using our vertex, we have:
x=a(y+1)²+2,
We know that the parabola goes through (5, 0),
so
we can use these coordinates to find the value of a:
5=a(0+1)²+2
5=a+2
a=5-2
a=3
x=3(y+1)²+2
the answer isa=3
see the attached figure
Answer:
x2-12x+3
Step-by-step explanation:
=x(x-3)-9(x-3)
=x2-3x-9x+3
=x2-12x+3
D. Multiply the top equation by 2
That way, 3y(2) - 6y = 6y - 6y = 0
hope this helps