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adoni [48]
2 years ago
15

Find the percent increase round to the nearest percent From 42 acres to 72 acres

Mathematics
1 answer:
Finger [1]2 years ago
5 0

Answer:

58.333333 percent

Step-by-step explanation:

58 percent

I took 42 divided by 72 times 100

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Which is eWhich is equivalent to 3 square root of 125quivalent to ?
Mkey [24]

Answer:

15\sqrt{5}

Step-by-step explanation:

3\sqrt{125}=3\sqrt{25*5}\\ =3\sqrt{25}*\sqrt{5}\\ =3*5*\sqrt{5}\\ =15\sqrt{5}

4 0
2 years ago
tingnan ang pattern.isulat sa sagutang papel ang nawawalang bilang. 1._1000_2000,3000 2.6330,6333,_6336_6339 3.650_750_850,950 4
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Lisandro fabrica juguetes. Si tiene 100 ruedas ¿Cuantos autos puede armar?<br> Me aydan porfa
AVprozaik [17]

Answer:

25

Step-by-step explanation:

un carro tiene 4 ruedas, entonces divide 100 por 4

100÷4=25

3 0
1 year ago
What is the constant in this expression? 3 x squared minus 2 x + y minus 4
cupoosta [38]
What are the numbers x and y are sopposed to be?
8 0
3 years ago
Read 2 more answers
In order to estimate the difference between the average hourly wages of employees of two branches of a department store, the fol
Julli [10]

Answer:

0.071,1.928

Step-by-step explanation:

                                                Downtown Store   North Mall Store

Sample size   n                             25                        20

Sample mean \bar{x}                         $9                        $8

Sample standard deviation  s       $2                        $1

n_1=25\\n_2=20

\bar{x_1}=9\\ \bar{x_2}=8

s_1=2\\s_2=1

x_1-x_2=9-8=1

Standard error of difference of means = \sqrt{\frac{s_1^2}{n_1}+\frac{s_2^2}{n_2}}

Standard error of difference of means = \sqrt{\frac{2^2}{25}+\frac{1^2}{20}}

Standard error of difference of means = 0.458

Degree of freedom = \frac{\sqrt{(\frac{s_1^2}{n_1}+\frac{s_2^2}{n_2}})^2}{\frac{(\frac{s_1^2}{n_1})^2}{n_1-1}+\frac{(\frac{s_2^2}{n_2})^2}{n_2-1}}

Degree of freedom = \frac{\sqrt{(\frac{2^2}{25}+\frac{1^2}{20}})^2}{\frac{(\frac{2^2}{25})^2}{25-1}+\frac{(\frac{1^2}{20})^2}{20-1}}

Degree of freedom =36

So, z value at 95% confidence interval and 36 degree of freedom = 2.0280

Confidence interval = (x_1-x_2)-z \times SE(x_1-x_2),(x_1-x_2)+z \times SE(x_1-x_2)

Confidence interval = 1-(2.0280)\times 0.458,1+(2.0280)\times 0.458

Confidence interval = 0.071,1.928

Hence Option A is true

Confidence interval is  0.071,1.928

4 0
2 years ago
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