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3 years ago

Find the percent increase round to the nearest percent From 42 acres to 72 acres

Mathematics

1 answer:

Finger [1]3 years ago

5 0

Answer:

58.333333 percent

Step-by-step explanation:

58 percent

I took 42 divided by 72 times 100

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Jacob made a banner for a sporting event in the shape of a parallelogram. The area of the banner is 127 1/2 square centimeters.

Bogdan [553]

Answer:

The base of the banner is 30 centimeters.

Step-by-step explanation:

Area = base × height

Plug in the numbers:

127 1/2 = b × 4 1/4

Convert mixed fractions into improper fractions for easier calculations.

Improper fraction formula: (denominator × mixed number + numerator)/denoninator

(2 × 127 + 1)/2 = 255/2

(4 × 4 + 1)/4 = 17/4

Rewrite equation:

255/2 = b × 17/4

Isolate variable b by multiplying the reciprocal of 17/4 (which is 4/17).

1020/34 = b

Simplify.

30 = b

5 0

3 years ago

A bacteria population doubles every minute. Explain why this population growth cant be modeled on a graph

Kisachek [45]

Answer:

It can be modeled on an exponential graph

Step-by-step explanation:

Bacteria is <u><em>doubling</em></u> by the minute. This means that if there are 2 bacteria in the first minute, there would be 4 in the second, 8 in the third, 16 in fourth, and so on. This can be modeled using an exponential graph, where a number is constantly increasing by multiplying.

3 0

3 years ago

Which point will correspond to the topmost point of the reflected figure? Please help.

Radda [10]

Answer:

Step-by-step explanation:

it will still be the same so the triangle is the same nothing changed

6 0

3 years ago

A university found that 20% of its students withdraw without completing the introductory statistics course. Assume that 20 stude

EleoNora [17]

Answer:

a) $P(X \leq 2)= P(X=0)+P(X=1)+P(X=2)$

And we can use the probability mass function and we got:

$P(X=0)=(20C0)(0.2)^0 (1-0.2)^{20-0}=0.0115$

$P(X=1)=(20C1)(0.2)^1 (1-0.2)^{20-1}=0.0576$

$P(X=2)=(20C2)(0.2)^2 (1-0.2)^{20-2}=0.1369$

And adding we got:

$P(X \leq 2)=0.0115+0.0576+0.1369 = 0.2061$

b) $P(X=4)=(20C4)(0.2)^4 (1-0.2)^{20-4}=0.2182$

c) $P(X>3) = 1-P(X \leq 3) = 1- [P(X=0)+P(X=1)+P(X=2)+P(X=3)]$

$P(X=0)=(20C0)(0.2)^0 (1-0.2)^{20-0}=0.0115$

$P(X=1)=(20C1)(0.2)^1 (1-0.2)^{20-1}=0.0576$

$P(X=2)=(20C2)(0.2)^2 (1-0.2)^{20-2}=0.1369$

$P(X=3)=(20C3)(0.2)^3 (1-0.2)^{20-3}=0.2054$

And replacing we got:

$P(X>3) = 1-[0.0115+0.0576+0.1369+0.2054]= 1-0.4114= 0.5886$

d) $E(X) = 20*0.2= 4$

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=20, p=0.2)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

Part a

We want this probability:

$P(X \leq 2)= P(X=0)+P(X=1)+P(X=2)$

And we can use the probability mass function and we got:

$P(X=0)=(20C0)(0.2)^0 (1-0.2)^{20-0}=0.0115$

$P(X=1)=(20C1)(0.2)^1 (1-0.2)^{20-1}=0.0576$

$P(X=2)=(20C2)(0.2)^2 (1-0.2)^{20-2}=0.1369$

And adding we got:

$P(X \leq 2)=0.0115+0.0576+0.1369 = 0.2061$

Part b

We want this probability:

$P(X=4)$

And using the probability mass function we got:

$P(X=4)=(20C4)(0.2)^4 (1-0.2)^{20-4}=0.2182$

Part c

We want this probability:

$P(X>3)$

We can use the complement rule and we got:

$P(X>3) = 1-P(X \leq 3) = 1- [P(X=0)+P(X=1)+P(X=2)+P(X=3)]$

$P(X=0)=(20C0)(0.2)^0 (1-0.2)^{20-0}=0.0115$

$P(X=1)=(20C1)(0.2)^1 (1-0.2)^{20-1}=0.0576$

$P(X=2)=(20C2)(0.2)^2 (1-0.2)^{20-2}=0.1369$

$P(X=3)=(20C3)(0.2)^3 (1-0.2)^{20-3}=0.2054$

And replacing we got:

$P(X>3) = 1-[0.0115+0.0576+0.1369+0.2054]= 1-0.4114= 0.5886$

Part d

The expected value is given by:

$E(X) = np$

And replacing we got:

$E(X) = 20*0.2= 4$

3 0

3 years ago

I don’t like to beg but I guess I’m in need..

djverab [1.8K]

Answer:

-4 < n ≤ 5

Step-by-step explanation:

Since the left inequality is an open circle and going to the right, the sign will be >

Since the right inequality sign is a closed circle and is going left, the sign would be ≤

The open circle ends at -4 so, n > -4

The closed circle ends at 5 so, n ≤ 5

You combine them and it looks like this:

-4 < n ≤ 5

6 0

3 years ago