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Readme [11.4K]
3 years ago
15

Whats 1 + 1 plz answer thisssssssssssssss

Mathematics
2 answers:
Makovka662 [10]3 years ago
6 0

Answer:

<h2>1+1 =2</h2>

hope it helps

<h3>stay safe healthy and happy...</h3>
kow [346]3 years ago
4 0

Answer:

1 + 1= 2

Step-by-step explanation:

because if u add 1 + 1 u will get 2

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What is the product 4^3* 4^-3
frozen [14]
Hey there! :D

Take care of the exponents. 

4^3= 4*4*4 

4^3= 64

4^-3

Make it a fraction to make the power positive. 

\frac{1}{4^3}

Now, simplify. 

\frac{1}{64}

64* 1/64= 1

The answer is 1. 

I hope this helps!
~kaikers
3 0
3 years ago
Read 2 more answers
What is the answer to 3/8 + 5/12=
Natasha_Volkova [10]
First, make the fractions both have common denominators, so 3/8= 9/24 and 5/12= 10/24. Then add them up and you get 19/24
3 0
4 years ago
Read 2 more answers
I need help with this
NeX [460]

Answer:

.25

Step-by-step explanation:

.5 x .5 = .25

6 0
3 years ago
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Find the area of each regular polygon. Round your answer to the nearest tenth if necessary.
tatuchka [14]

*I am assuming that the hexagons in all questions are regular and the triangle in (24) is equilateral*

(21)

Area of a Regular Hexagon: \frac{3\sqrt{3}}{2}(side)^{2} = \frac{3\sqrt{3}}{2}*(\frac{20\sqrt{3} }{3} )^{2} =200\sqrt{3} square units

(22)

Similar to (21)

Area = 216\sqrt{3} square units

(23)

For this case, we will have to consider the relation between the side and inradius of the hexagon. Since, a hexagon is basically a combination of six equilateral triangles, the inradius of the hexagon is basically the altitude of one of the six equilateral triangles. The relation between altitude of an equilateral triangle and its side is given by:

altitude=\frac{\sqrt{3}}{2}*side

side = \frac{36}{\sqrt{3}}

Hence, area of the hexagon will be: 648\sqrt{3} square units

(24)

Given is the inradius of an equilateral triangle.

Inradius = \frac{\sqrt{3}}{6}*side

Substituting the value of inradius and calculating the length of the side of the equilateral triangle:

Side = 16 units

Area of equilateral triangle = \frac{\sqrt{3}}{4}*(side)^{2} = \frac{\sqrt{3}}{4}*256 = 64\sqrt{3} square units

4 0
3 years ago
What is the correct answer?
Wittaler [7]
(b) (angle-side-angle) is correct.
6 0
3 years ago
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