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Dahasolnce [82]
3 years ago
12

Please help me its really important

Mathematics
1 answer:
Serga [27]3 years ago
5 0

Answer:

I think that the answer isssss B

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Using the following equation, find the center and radius:
rodikova [14]

Answer: 4) The center is located at (1, 3), and the radius is 6

Step-by-step explanation:

Solve the general equation of the circle.

x^2 -2x +1+ y^2-6y+9= 26+1+9 (x-1)^2+(y-3)^2=36=6^2

Hence, the coordinates of the center (1,3) And the radius will be 6

4 0
3 years ago
Rewrite using a single positive exponent. 3-6 -5​
yarga [219]

Answer:

1 \div {3}^{( 30)}

Step-by-step explanation:

There are exponent rules I posted above that are being used here.

We have (3^-6)^-5

Since we have a power times a power, we multiply 6 and 5 to get -30. Look at the first example in the photo.

So, we're left with 3^-30.

If you look at the photo, there's a rule for negative exponents.

Take the inverse of the base number, so 3 in this case:

1 / 3

and then make the exponent positive after taking the inverse.

So, we should get 1 / 3^30

Hope this helps!

3 0
2 years ago
Add the two expressions.<br><br> −4x+3 and 2x−6<br><br> Enter your answer in the box.
BlackZzzverrR [31]
First, you set your problem up like this: 

-4x+3=2x-6

add 6 to both sides so it looks like this:

-4x+9=2x

add 4x to both sides so it looks like this:

9=6x

divide 6 from both sides so this is your answer:

1.5=x
5 0
3 years ago
Read 2 more answers
Find the locus of the point (x,y) which is a distance 3 from the point (-2, 1)
Reptile [31]
Consider this option:
1. rule: Circle is the locus of the points which are on the same distance from the given point. Common view of the equation is: (x-a)²+(y-b)²=r², where r - the distance from the given point to the described locus, a&b - coordinates of the given point.
2. using item 1:
(x+2)²+(y-1)²=3² or (x+2)²+(y-1)²=9.
6 0
3 years ago
6. (5y+2)+14x=5y+ (2+14x)
svetoff [14.1K]
In my opinion it is C
4 0
3 years ago
Read 2 more answers
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