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larisa [96]
3 years ago
5

. Abraham's physics class has 40 students, and his class had an average (arithmetic mean) score of 75 on the midterm. Anita’s ph

ysics class has 20 students, and her class had an average score of 81 on the same midterm. What was the average score of all the students in both physics classes on the midterm?
Mathematics
2 answers:
VMariaS [17]3 years ago
8 0
A=4620/60=77 i am pretty sure
sergiy2304 [10]3 years ago
5 0
Average=(scores total)/(number of scores)

We are given two averages and two numbers of students so we can calculate the total scores in each class..

75=Ab/40, so the sum of Abraham's class scores is 40(75)=3000 and similarly
81=An/20, so the sum of Anita's class scores is 20(81)=1620

Now we know the total score for all the students is 3000+1620=4620

And we also know that there are a total fo 40+20=60 students, so the overall average for all the students is

a=4620/60=77
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Karo-lina-s [1.5K]

Answer:

Hence the simplification of \dfrac{66}{81} is \dfrac{22}{27}

Step-by-step explanation:

<em>" Simplification is the process of replacing a mathematical expression by an equivalent one, that is simpler (usually shorter), </em>

<em>for example</em><em>: Simplification of a fraction to an irreducible fraction ". </em>

Here we are given a fraction as:

\dfrac{66}{81}

As both the numerator and denominator are divisible by a factor of 3 hence we take out the common factor and obtain the reduced fraction which is further irreducible.

As 66=3×22  and 81=3×27

Hence \dfrac{66}{81}=\dfrac{3\times22}{3\times27}=\dfrac{22}{27}

Hence the simplification of \dfrac{66}{81} is \dfrac{22}{27}

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In the circle below, DB = 22 cm, and m&lt;DBC = 60°. Find BC. Ignore my handwriting.​
Karo-lina-s [1.5K]

Answer:

BC=11\ cm

Step-by-step explanation:

step 1

Find the measure of the arc DC

we know that

The inscribed angle measures half of the arc comprising

m\angle DBC=\frac{1}{2}[arc\ DC]

substitute the values

60\°=\frac{1}{2}[arc\ DC]

120\°=arc\ DC

arc\ DC=120\°

step 2

Find the measure of arc BC

we know that

arc\ DC+arc\ BC=180\° ----> because the diameter BD divide the circle into two equal parts

120\°+arc\ BC=180\°

arc\ BC=180\°-120\°=60\°

step 3

Find the measure of angle BDC

we know that

The inscribed angle measures half of the arc comprising

m\angle BDC=\frac{1}{2}[arc\ BC]

substitute the values

m\angle BDC=\frac{1}{2}[60\°]

m\angle BDC=30\°

therefore

The triangle DBC is a right triangle ---> 60°-30°-90°

step 4

Find the measure of BC

we know that

In the right triangle DBC

sin(\angle BDC)=BC/BD

BC=(BD)sin(\angle BDC)

substitute the values

BC=(22)sin(30\°)=11\ cm

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3 years ago
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