True or False: If you are tossing three dice, ={2,3,4,5,6}

A car has mass 1500 kg and is traveling at a speed of 35 miles/hour. what is its kinetic energy in joules? (Be sure to convert m

photoshop1234 [79]

Answer:

Factor by which kinetic energy increase = 4 times

Step-by-step explanation:

Given,

Mass of the car, v1 = 1500 kg

initial speed of car = 35 miles/h

$=\dfrac{35\times 1609.34}{3600}\ m/s$

= 15.64 m/s

Initial kinetic energy of the car is given by,

$k_1\ =\ \dfrac{1}{2}.m.v_1^2$

$=\ \dfrac{1}{2}\times 1500\times (15.64)^2\ joule$

= 183606.46 J

Final velocity of car v2 = 70 miles/hour

$=\dfrac{70\times 1609.34}{3600}$

= 31.29 m/s

So, final kinetic energy of car is given by

$k_2\ =\ \dfrac{1}{2}.m.v_2^2$

$=\ \dfrac{1}{2}\times 1500\times (31.29)^2$

= 734425.84 J

Now, the ratio of final to initial kinetic energy can be given by,

$\dfrac{k_2}{k_1}=\ \dfrac{734425.84}{183606.46}$

$=>\ k_2\ =\ 4k_1$

Hence, the kinetic energy will increase by 4 times.

7 0

3 years ago

WILL MARK BRAINLIEST!! PLZ HELP!!

olasank [31]

Answer:

The answer is D.

Step-by-step explanation:

When x=0, then y=300, so it has to be more than that.

When x=25, y=300, so it has to be less than that.

8 0

3 years ago

How is an equation like an expression? How is it different?

morpeh [17]

Answer:

See explanation.

Step-by-step explanation:

An expression is a set of terms that are combined using addition, subtraction, multiplication, or division. The following are examples of expressions:

$2x-1$

$5y+8$

$2$

Note: expressions do not equal anything.

In contrast, equations are expressions that equal at least one term. The following are examples of equations:

$2y-4=26$

$4x-4=0$

$x=10$

$y=x+2$

Note: equations do equal a term, as shown in the examples.

3 0

3 years ago

A copying machine reduces a 12 cm line to 10.5 cm

Dmitrij [34]

Answer:

14cm

Step-by-step explanation:

10.5 is 87.5% of 12, and 87.5% x 16 = 14

you can find the percentage by using 10.5/12 and x/100 to find x

10.5 * 100 = 1050

1050/12=87.5

7 0

3 years ago

Read 2 more answers

Messages arrive to a computer server according to a Poisson distribution with a mean rate of 11 per hour. Determine the length o

Zarrin [17]

Answer:

The length of the interval during which no messages arrive is 90 seconds long.

Step-by-step explanation:

Let X = number of messages arriving on a computer server in an hour.

The mean rate of the arrival of messages is, λ = 11/ hour.

The random variable X follows a Poisson distribution with parameter λ = 11.

The probability mass function of X is:

$P(X=x)=\frac{e^{-11}11^{x}}{x!};\ x=0,1,2,3....$

It is provided that in t hours the probability of receiving 0 messages is,

P (X = 0) = 0.76

Compute the value of t as follows:

$P(X=0)=\frac{e^{-11\times t}(11\times t)^{0}}{0!}\\0.76=e^{-11\times t}\\\ln(0.76)=-11\times t\\t=-\frac{\ln(0.76)}{11} \\=0.025\ hours\\\approx90\ seconds$

Thus, the length of the interval during which no messages arrive is 90 seconds long.

6 0

3 years ago