I think this is false because two opposite sides can't be perpendicular (creating a 90 degree angle) because opposite sides are parallel.
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Answer:
- (x -3)^2 +(y -5)^2 = 9
- x^2 +y^2 -6x -10y +25 = 0
Step-by-step explanation:
The standard form equation for a circle of radius r and center (h, k) is ...
(x -h)^2 +(y -k)^2 = r^2
For radius 3 and center (3, 5), this is ...
(x -3)^2 +(y -5)^2 = 9 . . . . standard form equation
Expanding this and subtracting the constant on the right gives ...
x^2 -6x +9 +y^2 -10y +25 -9 = 0
x^2 +y^2 -6x -10y +25 = 0 . . . . general form equation
Answer:
No
Step-by-step explanation:
when checking to see if a point satisfies a system of equations
plug in x and y values from your point into the system
(2, 10)
x y
-3(2) - 4(10) = 4. and. -5.2 + 10 = 2
-6-40 = 4. 4.8. = 2
-46 = 4.
invalid statement. invalid statement
therefore the point (2, 10) does not satisfy this system of equations.
Answer:
Hope it helps
Step-by-step explanation:
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