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Maru [420]
3 years ago
15

Messages arrive to a computer server according to a Poisson distribution with a mean rate of 11 per hour. Determine the length o

f an interval of time (in seconds) such that the probability that no messages arrive during this interval is 0.76. Round your answers to one decimal place (e.g. 98.7).
Mathematics
1 answer:
Zarrin [17]3 years ago
6 0

Answer:

The length of the interval during which no messages arrive is 90 seconds long.

Step-by-step explanation:

Let <em>X</em> = number of messages arriving on a computer server in an hour.

The mean rate of the arrival of messages is, <em>λ</em> = 11/ hour.

The random variable <em>X</em> follows a Poisson distribution with parameter <em>λ</em> = 11.

The probability mass function of <em>X</em> is:

P(X=x)=\frac{e^{-11}11^{x}}{x!};\ x=0,1,2,3....

It is provided that in <em>t</em> hours the probability of receiving 0 messages is,

P (X = 0) = 0.76

Compute the value of <em>t</em> as follows:

P(X=0)=\frac{e^{-11\times t}(11\times t)^{0}}{0!}\\0.76=e^{-11\times t}\\\ln(0.76)=-11\times t\\t=-\frac{\ln(0.76)}{11} \\=0.025\ hours\\\approx90\ seconds

Thus, the length of the interval during which no messages arrive is 90 seconds long.

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