Liz has 4/8 of cake and ruby and marks doesnt want it

Mathematics

1 answer:

ozzi3 years ago

8 0

Answer:

i dont get it- was there supposed to be an attachment??

Step-by-step explanation:

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A cylinder has a helght of 16 cm and a radius of 5 cm. A cone has a helght of 12 cm and a radius of 4 cm. If the cone is placed

erma4kov [3.2K]

Answer:

1055.04 cm³

Step-by-step explanation:

Given that,

Height of a cylinder, h = 16 cm

Radius of the cylinder, r = 5 cm

The height of a cone, h' = 12 cm

The radius of a cone, r' = 4 cm

The volume of the cylinder will be :

$V=\pi r^2 h\\\\=3.14\times 5^2\times 16\\\\=1256\ cm^3$

The volume of a cone is given by :

$V'=\dfrac{1}{3}\pi r^2 h\\\\=\dfrac{1}{3}\times 3.14\times (4)^2\times 12\\\\=200.96\ cm^3$

Volume of the air surrounding the cone Inside the cylinder = 1256 - 200.96 = 1055.04 cm³

Hence, the required answer is equal to 1055.04 cm³.

3 0

3 years ago

the half-life of strontium-90 is approximately 29 years. how much of a 500 g sample of strontium-90 will remain after 58 years

Yuliya22 [10]

Answer: 125 g

Step-by-step explanation:

$A = P_o\cdot e^{kt}\\\\\text{First, use the given information to find k:}\\\\\bullet A=\dfrac{1}{2}P_o\\\\\bullet k = unknown\\\\\bullet t=29\text{ years}\\\\\dfrac{1}{2}P_o=P_o\cdot e^{k(29)}\\\\\\\dfrac{1}{2}=e^{k(29)}\qquad divided\ both\ sides\ by\ P_o\\\\\\ln\bigg(\dfrac{1}{2}\bigg)=ln\bigg(e^{k(29)}\bigg)\qquad applied\ ln\ to\ both\ sides\\\\\\ln\bigg(\dfrac{1}{2}\bigg)=29k\qquad simplified-ln\ and\ e\ cancel\ out\\\\\\\dfrac{ln\bigg(\dfrac{1}{2}\bigg)}{29}=k\qquad divided\ 29\ from\ both\ sides\\\\\\-0.0239=k$

$\text{Now, use the following in the equation to solve for A:}\\\\\bullet A=unknown\\\bullet P_o=500\\\bullet k=-0.0239\\\bullet t=58\text{ years}\\\\A=500\cdot e^{(-0.0239)(58)}\\\\.\quad=500\cdot e^{-1.386}\\\\.\quad=125$